OCR MEI Paper 1 2021 November — Question 7 10 marks

Exam BoardOCR MEI
ModulePaper 1 (Paper 1)
Year2021
SessionNovember
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSimultaneous equations
TypeLine intersecting general conic
DifficultyStandard +0.3 This is a straightforward multi-part question requiring standard techniques: finding a circle equation from diameter endpoints (midpoint and distance formula), solving simultaneous equations (substitution into circle equation gives quadratic), and calculating triangle area (using coordinate formula or base×height). All steps are routine A-level methods with no novel insight required, making it slightly easier than average.
Spec1.02c Simultaneous equations: two variables by elimination and substitution1.02q Use intersection points: of graphs to solve equations1.03d Circles: equation (x-a)^2+(y-b)^2=r^21.03e Complete the square: find centre and radius of circle

7 In this question you must show detailed reasoning.
The points \(\mathrm { A } ( - 1,4 )\) and \(\mathrm { B } ( 7 , - 2 )\) are at opposite ends of a diameter of a circle.
  1. Find the equation of the circle.
  2. Find the coordinates of the points of intersection of the circle and the line \(y = 2 x + 5\).
  3. Q is the point of intersection with the larger \(y\)-coordinate. Calculate the area of the triangle ABQ .

Question 7(a):
AnswerMarks Guidance
AnswerMarks Guidance
Midpoint of AB is \((3, 1)\); Centre C of the circle is \((3, 1)\)B1 soi
Radius \(\sqrt{(7-3)^2 + (-2-1)^2} = 5\)M1 Attempt to find length of AB, AC or BC
So circle is \((x-3)^2 + (y-1)^2 = 25\)M1 A1 [4] Uses their midpoint and radius (do not allow diameter used). Need not be simplified
Question 7(b):
AnswerMarks Guidance
AnswerMarks Guidance
Crosses \(y = 2x + 5\) where \((x-3)^2 + (2x+5-1)^2 = 25\)M1 Substituting \(y = 2x+5\) and attempting to collect terms oe
\(5x^2 + 10x = 0\) giving \(x = -2, 0\)A1 A1 Both values correct. Allow for quadratic solved BC providing it is seen in form \(ax^2 + bx = 0\) or \(ay^2 + by + c = 0\)
So points are \((-2, 1)\) and \((0, 5)\)[3] Correct \(y\) coordinates FT their \(x\)-coordinates
Question 7(c):
AnswerMarks Guidance
AnswerMarks Guidance
\(AQ = \sqrt{2}\) and \(BQ = \sqrt{7^2 + 7^2} = 7\sqrt{2}\); Triangle ABQ has a right angle at Q (angle in a semicircle)M1 Attempt to find two lengths to be used in area calculation (excluding AB). Note QAB=81.9° and QBA=8.1°
So area of triangle is \(\frac{1}{2} \times AQ \times BQ\)M1 Correct method for finding the area
Area \(= 7\)A1 [3] FT their Q
## Question 7(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Midpoint of AB is $(3, 1)$; Centre C of the circle is $(3, 1)$ | B1 | soi |
| Radius $\sqrt{(7-3)^2 + (-2-1)^2} = 5$ | M1 | Attempt to find length of AB, AC or BC |
| So circle is $(x-3)^2 + (y-1)^2 = 25$ | M1 A1 [4] | Uses their midpoint and radius (do not allow diameter used). Need not be simplified |

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## Question 7(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Crosses $y = 2x + 5$ where $(x-3)^2 + (2x+5-1)^2 = 25$ | M1 | Substituting $y = 2x+5$ and attempting to collect terms oe |
| $5x^2 + 10x = 0$ giving $x = -2, 0$ | A1 A1 | Both values correct. Allow for quadratic solved BC providing it is seen in form $ax^2 + bx = 0$ or $ay^2 + by + c = 0$ |
| So points are $(-2, 1)$ and $(0, 5)$ | [3] | Correct $y$ coordinates FT their $x$-coordinates |

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## Question 7(c):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $AQ = \sqrt{2}$ and $BQ = \sqrt{7^2 + 7^2} = 7\sqrt{2}$; Triangle ABQ has a right angle at Q (angle in a semicircle) | M1 | Attempt to find two lengths to be used in area calculation (excluding AB). Note QAB=81.9° and QBA=8.1° |
| So area of triangle is $\frac{1}{2} \times AQ \times BQ$ | M1 | Correct method for finding the area |
| Area $= 7$ | A1 [3] | FT their Q |

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7 In this question you must show detailed reasoning.\\
The points $\mathrm { A } ( - 1,4 )$ and $\mathrm { B } ( 7 , - 2 )$ are at opposite ends of a diameter of a circle.
\begin{enumerate}[label=(\alph*)]
\item Find the equation of the circle.
\item Find the coordinates of the points of intersection of the circle and the line $y = 2 x + 5$.
\item Q is the point of intersection with the larger $y$-coordinate.

Calculate the area of the triangle ABQ .
\end{enumerate}

\hfill \mbox{\textit{OCR MEI Paper 1 2021 Q7 [10]}}