OCR MEI Paper 1 2021 November — Question 4 6 marks

Exam BoardOCR MEI
ModulePaper 1 (Paper 1)
Year2021
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSequences and Series
TypePeriodic Sequences
DifficultyModerate -0.8 This question tests basic definitions and standard formulas. Part (a) involves recognizing a periodic sequence and summing complete cycles (trivial arithmetic). Part (b) requires stating convergence conditions for geometric sequences and applying the infinite GP formula—both are direct recall with minimal problem-solving. Suitable for early Further Maths students with straightforward, textbook-style parts.
Spec1.04f Sequence types: increasing, decreasing, periodic1.04g Sigma notation: for sums of series1.04i Geometric sequences: nth term and finite series sum1.04j Sum to infinity: convergent geometric series |r|<1

4
  1. The first four terms of a sequence are \(2,3,0,3\) and the subsequent terms are given by \(\mathrm { a } _ { \mathrm { k } + 4 } = \mathrm { a } _ { \mathrm { k } }\).
    1. State what type of sequence this is.
    2. Find \(\sum _ { \mathrm { k } = 1 } ^ { 200 } \mathrm { a } _ { \mathrm { k } }\).
  2. A different sequence is given by \(\mathrm { u } _ { \mathrm { n } } = \mathrm { b } ^ { \mathrm { n } }\) where \(b\) is a constant and \(n \geqslant 1\).
    1. State the set of values of \(b\) for which this is a divergent sequence.
    2. In the case where \(b = \frac { 1 } { 3 }\), find the sum of all the terms in the sequence.

Question 4(a)(i):
AnswerMarks Guidance
AnswerMarks Guidance
Sequence is periodic [with period 4]B1 [1] Do not allow "repeating", "recurring" etc. Sequence can also be described as oscillating
Question 4(a)(ii):
AnswerMarks Guidance
AnswerMarks Guidance
Total of 200 terms is \(50 \times (2+3+0+3) = 400\)B1 [1] cao
Question 4(b)(i):
AnswerMarks Guidance
AnswerMarks Guidance
Sequence divergent for either \(b > 1\)B1 Allow for one correct inequality. Note for \(b=1\) the sequence is convergent, but the corresponding series is divergent
or \(b \leq -1\)B1 [2] Must have "or" or the union of sets. Condone \(b < -1\) or \(
Question 4(b)(ii):
AnswerMarks Guidance
AnswerMarks Guidance
Infinite sum of geometric series with \(a = \frac{1}{3}\), \(r = \frac{1}{3}\)M1 Using the sum of geometric series with \(r = \frac{1}{3}\)
\(S = \dfrac{a}{1-r} = \dfrac{\frac{1}{3}}{1 - \frac{1}{3}} = \dfrac{1}{2}\)A1 [2] www
## Question 4(a)(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Sequence is periodic [with period 4] | B1 [1] | Do not allow "repeating", "recurring" etc. Sequence can also be described as oscillating |

---

## Question 4(a)(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Total of 200 terms is $50 \times (2+3+0+3) = 400$ | B1 [1] | cao |

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## Question 4(b)(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Sequence divergent for either $b > 1$ | B1 | Allow for one correct inequality. Note for $b=1$ the sequence is convergent, but the corresponding series is divergent |
| or $b \leq -1$ | B1 [2] | Must have "or" or the union of sets. Condone $b < -1$ or $|b| > 1$ |

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## Question 4(b)(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Infinite sum of geometric series with $a = \frac{1}{3}$, $r = \frac{1}{3}$ | M1 | Using the sum of geometric series with $r = \frac{1}{3}$ |
| $S = \dfrac{a}{1-r} = \dfrac{\frac{1}{3}}{1 - \frac{1}{3}} = \dfrac{1}{2}$ | A1 [2] | www |

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4
\begin{enumerate}[label=(\alph*)]
\item The first four terms of a sequence are $2,3,0,3$ and the subsequent terms are given by $\mathrm { a } _ { \mathrm { k } + 4 } = \mathrm { a } _ { \mathrm { k } }$.
\begin{enumerate}[label=(\roman*)]
\item State what type of sequence this is.
\item Find $\sum _ { \mathrm { k } = 1 } ^ { 200 } \mathrm { a } _ { \mathrm { k } }$.
\end{enumerate}\item A different sequence is given by $\mathrm { u } _ { \mathrm { n } } = \mathrm { b } ^ { \mathrm { n } }$ where $b$ is a constant and $n \geqslant 1$.
\begin{enumerate}[label=(\roman*)]
\item State the set of values of $b$ for which this is a divergent sequence.
\item In the case where $b = \frac { 1 } { 3 }$, find the sum of all the terms in the sequence.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{OCR MEI Paper 1 2021 Q4 [6]}}