3 In this question you must show detailed reasoning.
Solve the equation \(\sec ^ { 2 } \theta + 2 \tan \theta = 4\) for \(0 ^ { \circ } \leqslant \theta < 360 ^ { \circ }\).
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Question 3:
Answer Marks
Guidance
Answer Marks
Guidance
\((1+\tan^2\theta) + 2\tan\theta = 4\) M1
Using appropriate trig identity; must attempt to reach equation with only one trig function
\(\tan^2\theta + 2\tan\theta - 3 = 0\) M1
Showing algebraic method for solving their quadratic
\((\tan\theta - 1)(\tan\theta + 3) = 0\)
When \(\tan\theta = 1\): \(\theta = 45°, 225°\) A1
Any two correct values for \(\theta\)
When \(\tan\theta = -3\): \(\theta = 108.4°, 288.4°\) A1 [4]
All correct values for \(\theta\) and no extras in interval; ignore values outside required interval
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## Question 3:
| Answer | Marks | Guidance |
|--------|-------|----------|
| $(1+\tan^2\theta) + 2\tan\theta = 4$ | M1 | Using appropriate trig identity; must attempt to reach equation with only one trig function |
| $\tan^2\theta + 2\tan\theta - 3 = 0$ | M1 | Showing algebraic method for solving their quadratic |
| $(\tan\theta - 1)(\tan\theta + 3) = 0$ | | |
| When $\tan\theta = 1$: $\theta = 45°, 225°$ | A1 | Any two correct values for $\theta$ |
| When $\tan\theta = -3$: $\theta = 108.4°, 288.4°$ | A1 [4] | All correct values for $\theta$ and no extras in interval; ignore values outside required interval |
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3 In this question you must show detailed reasoning.\\
Solve the equation $\sec ^ { 2 } \theta + 2 \tan \theta = 4$ for $0 ^ { \circ } \leqslant \theta < 360 ^ { \circ }$.
\hfill \mbox{\textit{OCR MEI Paper 1 2018 Q3 [4]}}