OCR MEI Paper 1 2018 June — Question 14

Exam BoardOCR MEI
ModulePaper 1 (Paper 1)
Year2018
SessionJune
TopicSUVAT & Travel Graphs

14 The velocity of a car, \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\) at time \(t\) seconds, is being modelled. Initially the car has velocity \(5 \mathrm {~ms} ^ { - 1 }\) and it accelerates to \(11.4 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) in 4 seconds. In model A, the acceleration is assumed to be uniform.
  1. Find an expression for the velocity of the car at time \(t\) using this model.
  2. Explain why this model is not appropriate in the long term. Model A is refined so that the velocity remains constant once the car reaches \(17.8 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
  3. Sketch a velocity-time graph for the motion of the car, making clear the time at which the acceleration changes.
  4. Calculate the displacement of the car in the first 20 seconds according to this refined model. In model B, the velocity of the car is given by $$v = \begin{cases} 5 + 0.6 t ^ { 2 } - 0.05 t ^ { 3 } & \text { for } 0 \leqslant t \leqslant 8
    17.8 & \text { for } 8 < t \leqslant 20 \end{cases}$$
  5. Show that this model gives an appropriate value for \(v\) when \(t = 4\).
  6. Explain why the value of the acceleration immediately before the velocity becomes constant is likely to mean that model B is a better model than model A.
  7. Show that model B gives the same value as model A for the displacement at time 20 s .