Standard +0.3 This is a straightforward proof following a given hint. Students let θ = arcsin x, immediately get sin θ = x and cos θ = y from the given equation, then apply sin²θ + cos²θ = 1 to reach x² + y² = 1. It requires only direct application of definitions and the Pythagorean identity with minimal problem-solving, making it slightly easier than average.
12 Given that \(\arcsin x = \arccos y\), prove that \(x ^ { 2 } + y ^ { 2 } = 1\). [Hint: Let \(\arcsin x = \theta\) ]
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12 Given that $\arcsin x = \arccos y$, prove that $x ^ { 2 } + y ^ { 2 } = 1$. [Hint: Let $\arcsin x = \theta$ ]
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\hfill \mbox{\textit{OCR MEI AS Paper 2 Q12 [3]}}