OCR MEI AS Paper 2 Specimen — Question 6 8 marks

Exam BoardOCR MEI
ModuleAS Paper 2 (AS Paper 2)
SessionSpecimen
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrig Graphs & Exact Values
TypeCalculate intersection coordinates algebraically
DifficultyChallenging +1.2 This question requires solving 3sin²θ = 2cosθ algebraically, which involves using sin²θ = 1-cos²θ to form a quadratic in cosθ, then solving and finding all solutions in the given range. While it requires multiple steps (substitution, quadratic formula, inverse trig, finding all solutions), these are standard A-level techniques with no novel insight needed. The algebraic manipulation is moderately challenging but routine for AS level.
Spec1.05f Trigonometric function graphs: symmetries and periodicities1.05o Trigonometric equations: solve in given intervals

6
  1. The graph of \(y = 3 \sin ^ { 2 } \theta\) for \(0 ^ { \circ } \leq \theta \leq 360 ^ { \circ }\) is shown in Fig. 6.
    On the copy of Fig. 6 in the Printed Answer Booklet, sketch the graph of \(y = 2 \cos \theta\) for \(0 ^ { \circ } \leq \theta \leq 360 ^ { \circ }\). \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{05376a51-e768-4b45-9c18-c98255a4bd70-05_818_1507_571_351} \captionsetup{labelformat=empty} \caption{Fig. 6}
    \end{figure}
  2. In this question you must show detailed reasoning. Determine the values of \(\theta , 0 ^ { \circ } \leq \theta \leq 360 ^ { \circ }\), for which the two graphs cross.

Question 6:
Part (a):
AnswerMarks Guidance
AnswerMarks Guidance
Correct cosine curve sketch with correct shape and symmetryB1 1.1a — Correct shape and symmetry for cosine graph
Correct maximum and minimum values shownB1 1.1 — Correct maximum and minimum values
[2]
Part (b):
AnswerMarks Guidance
AnswerMarks Guidance
DR: \(2\cos\theta = 3\sin^2\theta\)B1 1.2
\(2\cos\theta = 3(1 - \cos^2\theta)\)M1 3.1a — Correct use of identity must be seen
\(3\cos^2\theta + 2\cos\theta - 3 = 0\)M1 1.1 — Rearranging to zero must be seen, condone one error
\(\cos\theta = \frac{-1}{3} + \frac{\sqrt{10}}{3}\)A1 1.1 — Solve quadratic
\(\theta = 43.9°,\ 316.1°\)A1 1.1
\(\cos\theta = \frac{-1}{3} - \frac{\sqrt{10}}{3} < -1\) gives no solutionE1 2.4 — Or state that graph in part (i) only shows two solutions
[6]
# Question 6:

## Part (a):
| Answer | Marks | Guidance |
|--------|-------|----------|
| Correct cosine curve sketch with correct shape and symmetry | B1 | 1.1a — Correct shape and symmetry for cosine graph |
| Correct maximum and minimum values shown | B1 | 1.1 — Correct maximum and minimum values |
| **[2]** | | |

## Part (b):
| Answer | Marks | Guidance |
|--------|-------|----------|
| DR: $2\cos\theta = 3\sin^2\theta$ | B1 | 1.2 |
| $2\cos\theta = 3(1 - \cos^2\theta)$ | M1 | 3.1a — Correct use of identity **must be seen** |
| $3\cos^2\theta + 2\cos\theta - 3 = 0$ | M1 | 1.1 — Rearranging to zero **must be seen**, condone one error |
| $\cos\theta = \frac{-1}{3} + \frac{\sqrt{10}}{3}$ | A1 | 1.1 — Solve quadratic |
| $\theta = 43.9°,\ 316.1°$ | A1 | 1.1 |
| $\cos\theta = \frac{-1}{3} - \frac{\sqrt{10}}{3} < -1$ gives no solution | E1 | 2.4 — Or state that graph in part (i) only shows two solutions |
| **[6]** | | |

---
6
\begin{enumerate}[label=(\alph*)]
\item The graph of $y = 3 \sin ^ { 2 } \theta$ for $0 ^ { \circ } \leq \theta \leq 360 ^ { \circ }$ is shown in Fig. 6.\\
On the copy of Fig. 6 in the Printed Answer Booklet, sketch the graph of $y = 2 \cos \theta$ for $0 ^ { \circ } \leq \theta \leq 360 ^ { \circ }$.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{05376a51-e768-4b45-9c18-c98255a4bd70-05_818_1507_571_351}
\captionsetup{labelformat=empty}
\caption{Fig. 6}
\end{center}
\end{figure}
\item In this question you must show detailed reasoning.

Determine the values of $\theta , 0 ^ { \circ } \leq \theta \leq 360 ^ { \circ }$, for which the two graphs cross.
\end{enumerate}

\hfill \mbox{\textit{OCR MEI AS Paper 2  Q6 [8]}}