Easy -1.2 This is a straightforward single-step differentiation question requiring only recall of basic calculus rules (power rule) to find acceleration from velocity. It's simpler than average A-level questions as it involves no problem-solving, no context interpretation, and is purely mechanical application of dv/dt.
1 A particle moves along a straight line. Its velocity \(v \mathrm {~ms} ^ { - 1 }\) at time \(t\) s is given by \(\mathbf { v } = 2 \mathbf { t } + 0.6 \mathbf { t } ^ { 2 }\).
Find an expression for the acceleration of the particle at time \(t\).
1 A particle moves along a straight line. Its velocity $v \mathrm {~ms} ^ { - 1 }$ at time $t$ s is given by $\mathbf { v } = 2 \mathbf { t } + 0.6 \mathbf { t } ^ { 2 }$.\\
Find an expression for the acceleration of the particle at time $t$.
\hfill \mbox{\textit{OCR MEI AS Paper 1 2023 Q1 [2]}}