OCR MEI AS Paper 1 2022 June — Question 4 6 marks

Exam BoardOCR MEI
ModuleAS Paper 1 (AS Paper 1)
Year2022
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCompleting the square and sketching
TypeTransformations of quadratic graphs
DifficultyModerate -0.8 This is a straightforward multi-part question on completing the square and graph transformations. Part (a) is routine algebraic manipulation, part (b) requires reading the minimum from completed square form, and part (c) involves identifying a simple translation. All parts are standard textbook exercises requiring only recall and basic application of well-practiced techniques.
Spec1.02e Complete the square: quadratic polynomials and turning points1.02w Graph transformations: simple transformations of f(x)

4 The quadratic function \(\mathrm { f } ( x )\) is given by \(\mathrm { f } ( x ) = x ^ { 2 } - 3 x + 2\).
  1. Write \(\mathrm { f } ( x )\) in the form \(( \mathrm { x } + \mathrm { a } ) ^ { 2 } + \mathrm { b }\), where \(a\) and \(b\) are constants.
  2. Write down the coordinates of the minimum point on the graph of \(y = f ( x )\).
  3. Describe fully the transformation that maps the graph of \(y = f ( x )\) onto the graph of \(y = ( x + 1 ) ^ { 2 } - \frac { 1 } { 4 }\).

Question 4:
Part (a):
AnswerMarks Guidance
AnswerMarks Guidance
\(f(x) = x^2 - 3x + 2 = \left(x - \frac{3}{2}\right)^2 + b\)M1 Begins process of completing the square as far as \(\left(x-\frac{3}{2}\right)^2\). Also allow for \(\left(x+\frac{3}{2}\right)^2\)
\(= \left(x-\frac{3}{2}\right)^2 - \frac{1}{4}\)A1 All correct
Part (b):
AnswerMarks Guidance
AnswerMarks Guidance
Minimum point \(\left(\frac{3}{2}, -\frac{1}{4}\right)\)B1 \(x\)-coordinate FT their (a)
B1\(y\)-coordinate FT their (a)
Part (c):
AnswerMarks Guidance
AnswerMarks Guidance
translationB1 Correct term must be seen
\(\begin{pmatrix} -\frac{5}{2} \\ 0 \end{pmatrix}\)B1 Also allow for 2.5 to the left
## Question 4:

### Part (a):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $f(x) = x^2 - 3x + 2 = \left(x - \frac{3}{2}\right)^2 + b$ | M1 | Begins process of completing the square as far as $\left(x-\frac{3}{2}\right)^2$. Also allow for $\left(x+\frac{3}{2}\right)^2$ |
| $= \left(x-\frac{3}{2}\right)^2 - \frac{1}{4}$ | A1 | All correct |

### Part (b):
| Answer | Marks | Guidance |
|--------|-------|----------|
| Minimum point $\left(\frac{3}{2}, -\frac{1}{4}\right)$ | B1 | $x$-coordinate FT their (a) |
| | B1 | $y$-coordinate FT their (a) |

### Part (c):
| Answer | Marks | Guidance |
|--------|-------|----------|
| translation | B1 | Correct term must be seen |
| $\begin{pmatrix} -\frac{5}{2} \\ 0 \end{pmatrix}$ | B1 | Also allow for 2.5 to the left |

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4 The quadratic function $\mathrm { f } ( x )$ is given by $\mathrm { f } ( x ) = x ^ { 2 } - 3 x + 2$.
\begin{enumerate}[label=(\alph*)]
\item Write $\mathrm { f } ( x )$ in the form $( \mathrm { x } + \mathrm { a } ) ^ { 2 } + \mathrm { b }$, where $a$ and $b$ are constants.
\item Write down the coordinates of the minimum point on the graph of $y = f ( x )$.
\item Describe fully the transformation that maps the graph of $y = f ( x )$ onto the graph of $y = ( x + 1 ) ^ { 2 } - \frac { 1 } { 4 }$.
\end{enumerate}

\hfill \mbox{\textit{OCR MEI AS Paper 1 2022 Q4 [6]}}