CAIE P3 2019 November — Question 10 12 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2019
SessionNovember
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration by Substitution
TypeMulti-part questions combining substitution with curve/area analysis
DifficultyChallenging +1.2 Part (i) requires standard calculus (finding maximum via differentiation of a product/composite function) and numerical solving. Part (ii) is a straightforward substitution u = cos x that converts the integral into a polynomial form, requiring recognition that sin²x = 1 - cos²x. While it involves multiple techniques, these are standard P3/A-level Further Maths procedures with no novel insight required—slightly above average due to the algebraic manipulation needed after substitution.
Spec1.07r Chain rule: dy/dx = dy/du * du/dx and connected rates1.08h Integration by substitution

10 \includegraphics[max width=\textwidth, alt={}, center]{5b5ed7d1-028e-4f9a-ae9e-26071d0df678-18_449_787_262_678} The diagram shows the graph of \(y = \mathrm { e } ^ { \cos x } \sin ^ { 3 } x\) for \(0 \leqslant x \leqslant \pi\), and its maximum point \(M\). The shaded region \(R\) is bounded by the curve and the \(x\)-axis.
  1. Find the \(x\)-coordinate of \(M\). Show all necessary working and give your answer correct to 2 decimal places.
  2. By first using the substitution \(u = \cos x\), find the exact value of the area of \(R\).
    If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.

Question 10(i):
AnswerMarks Guidance
AnswerMark Guidance
Use product rule and chain rule at least onceM1
Obtain correct derivative in any formA1
Equate derivative to zero, use Pythagoras and obtain an equation in \(\cos x\)M1
Obtain \(\cos^2 x + 3\cos x - 1 = 0\), or 3-term equivalentA1
Obtain answer \(x = 1.26\)A1
Total: 5 marks
Question 10(ii):
AnswerMarks Guidance
AnswerMark Guidance
Using \(du = \pm \sin x \, dx\) express integrand in terms of \(u\) and \(du\)M1
Obtain integrand \(e^u(u^2 - 1)\)A1 OE
Commence integration by parts and reach \(ae^u(u^2-1) + b\int ue^u \, du\)\*M1
Obtain \(e^u(u^2-1) - 2\int ue^u \, du\)A1 OE
Complete integration, obtaining \(e^u(u^2 - 2u + 1)\)A1 OE
Substitute limits \(u = 1\) and \(u = -1\) (or \(x = 0\) and \(x = \pi\)), having integrated completelyDM1
Obtain answer \(\frac{4}{e}\), or exact equivalentA1
Total: 7 marks
## Question 10(i):

| Answer | Mark | Guidance |
|--------|------|----------|
| Use product rule and chain rule at least once | M1 | |
| Obtain correct derivative in any form | A1 | |
| Equate derivative to zero, use Pythagoras and obtain an equation in $\cos x$ | M1 | |
| Obtain $\cos^2 x + 3\cos x - 1 = 0$, or 3-term equivalent | A1 | |
| Obtain answer $x = 1.26$ | A1 | |

**Total: 5 marks**

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## Question 10(ii):

| Answer | Mark | Guidance |
|--------|------|----------|
| Using $du = \pm \sin x \, dx$ express integrand in terms of $u$ and $du$ | M1 | |
| Obtain integrand $e^u(u^2 - 1)$ | A1 | OE |
| Commence integration by parts and reach $ae^u(u^2-1) + b\int ue^u \, du$ | \*M1 | |
| Obtain $e^u(u^2-1) - 2\int ue^u \, du$ | A1 | OE |
| Complete integration, obtaining $e^u(u^2 - 2u + 1)$ | A1 | OE |
| Substitute limits $u = 1$ and $u = -1$ (or $x = 0$ and $x = \pi$), having integrated completely | DM1 | |
| Obtain answer $\frac{4}{e}$, or exact equivalent | A1 | |

**Total: 7 marks**
10\\
\includegraphics[max width=\textwidth, alt={}, center]{5b5ed7d1-028e-4f9a-ae9e-26071d0df678-18_449_787_262_678}

The diagram shows the graph of $y = \mathrm { e } ^ { \cos x } \sin ^ { 3 } x$ for $0 \leqslant x \leqslant \pi$, and its maximum point $M$. The shaded region $R$ is bounded by the curve and the $x$-axis.\\
(i) Find the $x$-coordinate of $M$. Show all necessary working and give your answer correct to 2 decimal places.\\

(ii) By first using the substitution $u = \cos x$, find the exact value of the area of $R$.\\

If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.\\

\hfill \mbox{\textit{CAIE P3 2019 Q10 [12]}}