CAIE P3 2019 November — Question 8 10 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2019
SessionNovember
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNumerical integration
TypeOver/underestimate justification with graph
DifficultyStandard +0.3 This is a straightforward multi-part question testing standard techniques: trapezium rule application (routine calculation), understanding concavity to determine over/underestimate (conceptual but basic), and differentiation of sec x followed by solving an equation. All parts are textbook-standard with no novel insight required, making it slightly easier than average.
Spec1.07k Differentiate trig: sin(kx), cos(kx), tan(kx)1.09f Trapezium rule: numerical integration

8 \includegraphics[max width=\textwidth, alt={}, center]{5b5ed7d1-028e-4f9a-ae9e-26071d0df678-14_604_497_262_822} The diagram shows the graph of \(y = \sec x\) for \(0 \leqslant x < \frac { 1 } { 2 } \pi\).
  1. Use the trapezium rule with 2 intervals to estimate the value of \(\int _ { 0 } ^ { 1.2 } \sec x \mathrm {~d} x\), giving your answer correct to 2 decimal places.
  2. Explain, with reference to the diagram, whether the trapezium rule gives an overestimate or an underestimate of the true value of the integral in part (i).
  3. \(P\) is the point on the part of the curve \(y = \sec x\) for \(0 \leqslant x < \frac { 1 } { 2 } \pi\) at which the gradient is 2 . By first differentiating \(\frac { 1 } { \cos x }\), find the \(x\)-coordinate of \(P\), giving your answer correct to 3 decimal places.

Question 8(i):
AnswerMarks Guidance
AnswerMark Guidance
State or imply ordinates \(1, 1.2116\ldots, 2.7597\ldots\)B1
Use correct formula, or equivalent, with \(h = 0.6\)M1
Obtain answer 1.85A1
Question 8(ii):
AnswerMarks Guidance
AnswerMark Guidance
Explain why the rule gives an overestimateB1
Question 8(iii):
AnswerMarks Guidance
AnswerMark Guidance
Differentiate using quotient or chain ruleM1
Obtain correct derivative in terms of \(\sin x\) and \(\cos x\)A1
Equate derivative to 2, use Pythagoras and obtain an equation in \(\sin x\)M1
Obtain \(2\sin^2 x + \sin x - 2 = 0\)A1 OE
Solve a 3-term quadratic for \(x\)M1
Obtain answer \(x = 0.896\) onlyA1
## Question 8(i):

| Answer | Mark | Guidance |
|--------|------|----------|
| State or imply ordinates $1, 1.2116\ldots, 2.7597\ldots$ | B1 | |
| Use correct formula, or equivalent, with $h = 0.6$ | M1 | |
| Obtain answer 1.85 | A1 | |

## Question 8(ii):

| Answer | Mark | Guidance |
|--------|------|----------|
| Explain why the rule gives an overestimate | B1 | |

## Question 8(iii):

| Answer | Mark | Guidance |
|--------|------|----------|
| Differentiate using quotient or chain rule | M1 | |
| Obtain correct derivative in terms of $\sin x$ and $\cos x$ | A1 | |
| Equate derivative to 2, use Pythagoras and obtain an equation in $\sin x$ | M1 | |
| Obtain $2\sin^2 x + \sin x - 2 = 0$ | A1 | OE |
| Solve a 3-term quadratic for $x$ | M1 | |
| Obtain answer $x = 0.896$ only | A1 | |
8\\
\includegraphics[max width=\textwidth, alt={}, center]{5b5ed7d1-028e-4f9a-ae9e-26071d0df678-14_604_497_262_822}

The diagram shows the graph of $y = \sec x$ for $0 \leqslant x < \frac { 1 } { 2 } \pi$.\\
(i) Use the trapezium rule with 2 intervals to estimate the value of $\int _ { 0 } ^ { 1.2 } \sec x \mathrm {~d} x$, giving your answer correct to 2 decimal places.\\

(ii) Explain, with reference to the diagram, whether the trapezium rule gives an overestimate or an underestimate of the true value of the integral in part (i).\\

(iii) $P$ is the point on the part of the curve $y = \sec x$ for $0 \leqslant x < \frac { 1 } { 2 } \pi$ at which the gradient is 2 . By first differentiating $\frac { 1 } { \cos x }$, find the $x$-coordinate of $P$, giving your answer correct to 3 decimal places.\\

\hfill \mbox{\textit{CAIE P3 2019 Q8 [10]}}