- Given that \(a > b > 0\) and that \(a\) and \(b\) satisfy the equation
$$\log a - \log b = \log ( a - b )$$
- show that
$$a = \frac { b ^ { 2 } } { b - 1 }$$
(3)
- Write down the full restriction on the value of \(b\), explaining the reason for this restriction.