Edexcel AS Paper 1 Specimen — Question 7 8 marks

Exam BoardEdexcel
ModuleAS Paper 1 (AS Paper 1)
SessionSpecimen
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeStandard product of two binomials
DifficultyModerate -0.8 This is a straightforward multi-part binomial expansion question requiring routine application of the binomial theorem and basic algebraic manipulation. Part (a) is trivial expansion of a squared binomial, part (b) is standard binomial theorem application with fractional coefficients, and part (c) involves multiplying polynomials to find a specific coefficient—all mechanical processes with no problem-solving insight required, making it easier than average.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

  1. (a) Expand \(\left( 1 + \frac { 3 } { x } \right) ^ { 2 }\) simplifying each term.
    (b) Use the binomial expansion to find, in ascending powers of \(x\), the first four terms in the expansion of
$$\left( 1 + \frac { 3 } { 4 } x \right) ^ { 6 }$$ simplifying each term.
(c) Hence find the coefficient of \(x\) in the expansion of $$\left( 1 + \frac { 3 } { x } \right) ^ { 2 } \left( 1 + \frac { 3 } { 4 } x \right) ^ { 6 }$$

Question 7:
Part (a):
AnswerMarks Guidance
WorkingMark Guidance
\(\left(1+\frac{3}{x}\right)^2 = 1+\frac{6}{x}+\frac{9}{x^2}\)M1 Attempts \(\left(1+\frac{3}{x}\right)^2 = A+\frac{B}{x}+\frac{C}{x^2}\)
Correct equation \(1+\frac{6}{x}+\frac{9}{x^2}\)A1 Fully correct
Part (b):
AnswerMarks Guidance
WorkingMark Guidance
\(\left(1+\frac{3}{4}x\right)^6 = 1+6\times\left(\frac{3}{4}x\right)+...\)B1 First two terms correct, may be unsimplified
\(1+6\times\left(\frac{3}{4}x\right)+\frac{6\times5}{2}\times\left(\frac{3}{4}x\right)^2+\frac{6\times5\times4}{3\times2}\times\left(\frac{3}{4}x\right)^3+...\)M1 Attempts binomial expansion; correct coefficient and power of \(x\) seen at least once in term 3 or 4
Unsimplified expansion correctA1 Binomial expansion correct and unsimplified
\(= 1+\frac{9}{2}x+\frac{135}{16}x^2+\frac{135}{16}x^3+...\)A1 Binomial expansion correct and simplified
Part (c):
AnswerMarks Guidance
WorkingMark Guidance
\(\left(1+\frac{3}{x}\right)^2\left(1+\frac{3}{4}x\right)^6 = \left(1+\frac{6}{x}+\frac{9}{x^2}\right)\left(1+\frac{9}{2}x+\frac{135}{16}x^2+\frac{135}{16}x^3+...\right)\)M1 Combines all relevant terms for \(\left(1+\frac{A}{x}+\frac{B}{x^2}\right)\left(1+Cx+Dx^2+Ex^3+...\right)\) to find coefficient of \(x\)
Coefficient of \(x = \frac{9}{2}+6\times\frac{135}{16}+9\times\frac{135}{16} = \frac{2097}{16}\)A1 Fully correct
## Question 7:

### Part (a):
| Working | Mark | Guidance |
|---------|------|----------|
| $\left(1+\frac{3}{x}\right)^2 = 1+\frac{6}{x}+\frac{9}{x^2}$ | M1 | Attempts $\left(1+\frac{3}{x}\right)^2 = A+\frac{B}{x}+\frac{C}{x^2}$ |
| Correct equation $1+\frac{6}{x}+\frac{9}{x^2}$ | A1 | Fully correct |

### Part (b):
| Working | Mark | Guidance |
|---------|------|----------|
| $\left(1+\frac{3}{4}x\right)^6 = 1+6\times\left(\frac{3}{4}x\right)+...$ | B1 | First two terms correct, may be unsimplified |
| $1+6\times\left(\frac{3}{4}x\right)+\frac{6\times5}{2}\times\left(\frac{3}{4}x\right)^2+\frac{6\times5\times4}{3\times2}\times\left(\frac{3}{4}x\right)^3+...$ | M1 | Attempts binomial expansion; correct coefficient and power of $x$ seen at least once in term 3 or 4 |
| Unsimplified expansion correct | A1 | Binomial expansion correct and unsimplified |
| $= 1+\frac{9}{2}x+\frac{135}{16}x^2+\frac{135}{16}x^3+...$ | A1 | Binomial expansion correct and simplified |

### Part (c):
| Working | Mark | Guidance |
|---------|------|----------|
| $\left(1+\frac{3}{x}\right)^2\left(1+\frac{3}{4}x\right)^6 = \left(1+\frac{6}{x}+\frac{9}{x^2}\right)\left(1+\frac{9}{2}x+\frac{135}{16}x^2+\frac{135}{16}x^3+...\right)$ | M1 | Combines all relevant terms for $\left(1+\frac{A}{x}+\frac{B}{x^2}\right)\left(1+Cx+Dx^2+Ex^3+...\right)$ to find coefficient of $x$ |
| Coefficient of $x = \frac{9}{2}+6\times\frac{135}{16}+9\times\frac{135}{16} = \frac{2097}{16}$ | A1 | Fully correct |

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\begin{enumerate}
  \item (a) Expand $\left( 1 + \frac { 3 } { x } \right) ^ { 2 }$ simplifying each term.\\
(b) Use the binomial expansion to find, in ascending powers of $x$, the first four terms in the expansion of
\end{enumerate}

$$\left( 1 + \frac { 3 } { 4 } x \right) ^ { 6 }$$

simplifying each term.\\
(c) Hence find the coefficient of $x$ in the expansion of

$$\left( 1 + \frac { 3 } { x } \right) ^ { 2 } \left( 1 + \frac { 3 } { 4 } x \right) ^ { 6 }$$

\hfill \mbox{\textit{Edexcel AS Paper 1  Q7 [8]}}