Edexcel AS Paper 1 Specimen — Question 1 6 marks

Exam BoardEdexcel
ModuleAS Paper 1 (AS Paper 1)
SessionSpecimen
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStationary points and optimisation
TypeFind range where function increasing/decreasing
DifficultyModerate -0.8 This is a straightforward application of differentiation requiring polynomial differentiation (routine), setting derivative > 0, and solving a quadratic inequality. All steps are standard AS-level techniques with no problem-solving insight needed, making it easier than average but not trivial.
Spec1.07i Differentiate x^n: for rational n and sums1.07o Increasing/decreasing: functions using sign of dy/dx

  1. A curve has equation
$$y = 2 x ^ { 3 } - 2 x ^ { 2 } - 2 x + 8$$
  1. Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\)
  2. Hence find the range of values of \(x\) for which \(y\) is increasing. Write your answer in set notation.
    VIIIV SIHI NI JIIYM IONOOVIUV SIHI NI JIIAM ION OOVI4V SIHI NI JIIIM I ON OO

Question 1(a)
\(y = 2x^3 - 2x^2 - 2x + 8\)
AnswerMarks Guidance
\(\frac{dy}{dx} = 6x^2 - 4x - 2\)M1 A1
(2 marks)
Question 1(b)
AnswerMarks Guidance
Attempts \(6x^2 - 4x - 2 \geq 0\)M1 1.1b
\((6x + 2)(x - 1) \geq 0\)M1 1.1b
\(x = -\frac{1}{3}, 1\)A1 1.1b
Chooses outside regionM1 1.1b
\(\{x : x \leq -\frac{1}{3}\} \cup \{x : x \geq 1\}\)A1 2.5
(4 marks)
Notes:
Part (a):
M1: Attempts to differentiate. Allow two correct terms unsimplified.
A1: \(\frac{dy}{dx} = 6x^2 - 4x - 2\)
Part (b):
M1: Attempts to find critical values of \(\frac{dy}{dx} \geq 0\) or \(\frac{dy}{dx} = 0\)
A1: Correct critical values \(x = -\frac{1}{3}, 1\)
M1: Chooses the outside region
A1: \(\{x : x \leq -\frac{1}{3}\} \cup \{x : x \geq 1\}\) or \(\{x : x \in \mathbb{R}, x \leq -\frac{1}{3}\) or \(x \geq 1\}\)
Accept also \(\{x : x \not\geq -\frac{1}{3}\} \cup \{x : x \not\leq 1\}\)
Question 1(b) — Vectors
AnswerMarks Guidance
Explains that \(OC\) is parallel to \(AB\) as \(8\mathbf{i} - 20\mathbf{j} = 4(2\mathbf{i} - 5\mathbf{j})\)M1 1.1b
As \(OC = 4AB\) it is parallel to it and not the same length
AnswerMarks Guidance
Hence \(OABC\) is a trapezium.A1 2.4
(2 marks)
Notes:
Part (a):
M1: Attempts \(\mathbf{AB} = \mathbf{OB} - \mathbf{OA}\) or equivalent. This may be implied by one correct component.
A1: \(2\mathbf{i} - 5\mathbf{j}\)
Part (b):
M1: Attempts to compare vectors \(\mathbf{OC}\) and \(\mathbf{AB}\) by considering their directions
A1: Fully explains why \(OABC\) is a trapezium. (The candidate is required to state that \(OC\) is parallel to \(AB\) but not the same length as it.)
# Question 1(a)

$y = 2x^3 - 2x^2 - 2x + 8$

$\frac{dy}{dx} = 6x^2 - 4x - 2$ | M1 | A1 | 1.1b

(2 marks)

# Question 1(b)

Attempts $6x^2 - 4x - 2 \geq 0$ | M1 | 1.1b

$(6x + 2)(x - 1) \geq 0$ | M1 | 1.1b

$x = -\frac{1}{3}, 1$ | A1 | 1.1b

Chooses outside region | M1 | 1.1b

$\{x : x \leq -\frac{1}{3}\} \cup \{x : x \geq 1\}$ | A1 | 2.5

(4 marks)

**Notes:**

**Part (a):**

M1: Attempts to differentiate. Allow two correct terms unsimplified.

A1: $\frac{dy}{dx} = 6x^2 - 4x - 2$

**Part (b):**

M1: Attempts to find critical values of $\frac{dy}{dx} \geq 0$ or $\frac{dy}{dx} = 0$

A1: Correct critical values $x = -\frac{1}{3}, 1$

M1: Chooses the outside region

A1: $\{x : x \leq -\frac{1}{3}\} \cup \{x : x \geq 1\}$ or $\{x : x \in \mathbb{R}, x \leq -\frac{1}{3}$ or $x \geq 1\}$

Accept also $\{x : x \not\geq -\frac{1}{3}\} \cup \{x : x \not\leq 1\}$

---

# Question 1(b) — Vectors

Explains that $OC$ is parallel to $AB$ as $8\mathbf{i} - 20\mathbf{j} = 4(2\mathbf{i} - 5\mathbf{j})$ | M1 | 1.1b

As $OC = 4AB$ it is parallel to it and not the same length

Hence $OABC$ is a trapezium. | A1 | 2.4

(2 marks)

**Notes:**

**Part (a):**

M1: Attempts $\mathbf{AB} = \mathbf{OB} - \mathbf{OA}$ or equivalent. This may be implied by one correct component.

A1: $2\mathbf{i} - 5\mathbf{j}$

**Part (b):**

M1: Attempts to compare vectors $\mathbf{OC}$ and $\mathbf{AB}$ by considering their directions

A1: Fully explains why $OABC$ is a trapezium. (The candidate is required to state that $OC$ is parallel to $AB$ but not the same length as it.)
\begin{enumerate}
  \item A curve has equation
\end{enumerate}

$$y = 2 x ^ { 3 } - 2 x ^ { 2 } - 2 x + 8$$

(a) Find $\frac { \mathrm { d } y } { \mathrm {~d} x }$\\
(b) Hence find the range of values of $x$ for which $y$ is increasing. Write your answer in set notation.

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\hline
VIIIV SIHI NI JIIYM IONOO & VIUV SIHI NI JIIAM ION OO & VI4V SIHI NI JIIIM I ON OO \\
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\end{center}

\hfill \mbox{\textit{Edexcel AS Paper 1  Q1 [6]}}