Edexcel AS Paper 1 2021 November — Question 5 6 marks

Exam BoardEdexcel
ModuleAS Paper 1 (AS Paper 1)
Year2021
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTangents, normals and gradients
TypeFind derivative of simple polynomial (integer powers)
DifficultyModerate -0.8 This is a straightforward AS-level differentiation question requiring basic power rule application and understanding of the derivative as a limit. Part (a) is routine differentiation, part (b) is chord gradient using the difference quotient formula, and part (c) tests conceptual understanding that the tangent gradient is the limit as h→0. All techniques are standard with no problem-solving insight required.
Spec1.07a Derivative as gradient: of tangent to curve1.07b Gradient as rate of change: dy/dx notation

5. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{235cd1dc-a3ab-473a-bf77-3e41b274dfd8-10_680_684_255_694} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} Figure 1 shows part of the curve with equation \(y = 3 x ^ { 2 } - 2\) The point \(P ( 2,10 )\) lies on the curve.
  1. Find the gradient of the tangent to the curve at \(P\). The point \(Q\) with \(x\) coordinate \(2 + h\) also lies on the curve.
  2. Find the gradient of the line \(P Q\), giving your answer in terms of \(h\) in simplest form.
  3. Explain briefly the relationship between part (b) and the answer to part (a).

Question 5:
Part (a):
AnswerMarks Guidance
Working/AnswerMarks Guidance
Attempts \(\frac{dy}{dx}\) at \(x=2\)M1 Allow \(3x^2 - 2 \to \ldots x\) and substitutes \(x=2\)
\(\frac{dy}{dx} = 6x \Rightarrow\) gradient at \(P\) is \(12\)A1 cso
Part (b):
AnswerMarks Guidance
Working/AnswerMarks Guidance
Gradient \(PQ = \dfrac{3(2+h)^2-2-10}{(2+h)-2}\)B1 Correct expression for gradient of chord, seen or implied
\(= \dfrac{3(2+h)^2-12}{(2+h)-2} = \dfrac{12h+3h^2}{h}\)M1 Attempts \(\frac{\delta y}{\delta x}\), condoning slips; denominator must be \(h\)
\(= 12+3h\)A1 cso
Part (c):
AnswerMarks Guidance
Working/AnswerMarks Guidance
As \(h\to 0\), \(12+3h \to 12\); gradient of chord tends to gradient of tangent to the curveB1 Must state \(h\to 0\) and \(12+3h\to 12\) AND state chord gradient tends to gradient of curve
# Question 5:

## Part (a):

| Working/Answer | Marks | Guidance |
|---|---|---|
| Attempts $\frac{dy}{dx}$ at $x=2$ | M1 | Allow $3x^2 - 2 \to \ldots x$ and substitutes $x=2$ |
| $\frac{dy}{dx} = 6x \Rightarrow$ gradient at $P$ is $12$ | A1 | cso |

## Part (b):

| Working/Answer | Marks | Guidance |
|---|---|---|
| Gradient $PQ = \dfrac{3(2+h)^2-2-10}{(2+h)-2}$ | B1 | Correct expression for gradient of chord, seen or implied |
| $= \dfrac{3(2+h)^2-12}{(2+h)-2} = \dfrac{12h+3h^2}{h}$ | M1 | Attempts $\frac{\delta y}{\delta x}$, condoning slips; denominator must be $h$ |
| $= 12+3h$ | A1 | cso |

## Part (c):

| Working/Answer | Marks | Guidance |
|---|---|---|
| As $h\to 0$, $12+3h \to 12$; gradient of chord tends to gradient of tangent to the curve | B1 | Must state $h\to 0$ and $12+3h\to 12$ AND state chord gradient tends to gradient of curve |

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5.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{235cd1dc-a3ab-473a-bf77-3e41b274dfd8-10_680_684_255_694}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}

Figure 1 shows part of the curve with equation $y = 3 x ^ { 2 } - 2$\\
The point $P ( 2,10 )$ lies on the curve.
\begin{enumerate}[label=(\alph*)]
\item Find the gradient of the tangent to the curve at $P$.

The point $Q$ with $x$ coordinate $2 + h$ also lies on the curve.
\item Find the gradient of the line $P Q$, giving your answer in terms of $h$ in simplest form.
\item Explain briefly the relationship between part (b) and the answer to part (a).
\end{enumerate}

\hfill \mbox{\textit{Edexcel AS Paper 1 2021 Q5 [6]}}