Edexcel AS Paper 1 2021 November — Question 7 5 marks

Exam BoardEdexcel
ModuleAS Paper 1 (AS Paper 1)
Year2021
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSine and Cosine Rules
TypeParallelogram problems
DifficultyStandard +0.3 This is a straightforward application of the parallelogram area formula (area = ab sin θ) to find an angle, followed by using the cosine rule. Both parts are standard textbook exercises requiring direct formula application with no problem-solving insight needed. Slightly easier than average due to the routine nature of the calculations.
Spec1.05b Sine and cosine rules: including ambiguous case1.05c Area of triangle: using 1/2 ab sin(C)

  1. A parallelogram \(P Q R S\) has area \(50 \mathrm {~cm} ^ { 2 }\)
Given
  • \(P Q\) has length 14 cm
  • \(Q R\) has length 7 cm
  • angle \(S P Q\) is obtuse
    find
    1. the size of angle \(S P Q\), in degrees, to 2 decimal places,
    2. the length of the diagonal \(S Q\), in cm , to one decimal place.

Question 7:
Part (a):
AnswerMarks Guidance
Working/AnswerMarks Guidance
\(50 = 7\times14\sin(SPQ)\)B1 Sets up area formula correctly
\(180° - \arcsin\!\left(\dfrac{50}{98}\right)\)M1 Correct method to find obtuse \(\angle SPQ\)
\(= 149.32°\)A1 awrt \(149.32°\)
Part (b):
AnswerMarks Guidance
Working/AnswerMarks Guidance
\(SQ^2 = 14^2+7^2-2\times14\times7\cos(149.32°)\)M1 Correct method using their \(\angle SPQ\)
\(SQ = 20.3\text{ cm}\)A1 awrt \(20.3\) cm; condone lack of units
# Question 7:

## Part (a):

| Working/Answer | Marks | Guidance |
|---|---|---|
| $50 = 7\times14\sin(SPQ)$ | B1 | Sets up area formula correctly |
| $180° - \arcsin\!\left(\dfrac{50}{98}\right)$ | M1 | Correct method to find obtuse $\angle SPQ$ |
| $= 149.32°$ | A1 | awrt $149.32°$ |

## Part (b):

| Working/Answer | Marks | Guidance |
|---|---|---|
| $SQ^2 = 14^2+7^2-2\times14\times7\cos(149.32°)$ | M1 | Correct method using their $\angle SPQ$ |
| $SQ = 20.3\text{ cm}$ | A1 | awrt $20.3$ cm; condone lack of units |
\begin{enumerate}
  \item A parallelogram $P Q R S$ has area $50 \mathrm {~cm} ^ { 2 }$
\end{enumerate}

Given

\begin{itemize}
  \item $P Q$ has length 14 cm
  \item $Q R$ has length 7 cm
  \item angle $S P Q$ is obtuse\\
find\\
(a) the size of angle $S P Q$, in degrees, to 2 decimal places,\\
(b) the length of the diagonal $S Q$, in cm , to one decimal place.
\end{itemize}

\hfill \mbox{\textit{Edexcel AS Paper 1 2021 Q7 [5]}}