CAIE P3 2017 November — Question 5 7 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2017
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferential equations
TypeSeparable variables - standard (polynomial/exponential x-side)
DifficultyModerate -0.3 This is a straightforward separable variables question requiring standard technique: separate variables, integrate both sides (one side needs partial fractions), then apply initial condition. The partial fractions decomposition is simple and all steps are routine for P3 level, making it slightly easier than average but not trivial.
Spec1.08k Separable differential equations: dy/dx = f(x)g(y)

5 The variables \(x\) and \(y\) satisfy the differential equation $$( x + 1 ) \frac { \mathrm { d } y } { \mathrm {~d} x } = y ( x + 2 )$$ and it is given that \(y = 2\) when \(x = 1\). Solve the differential equation and obtain an expression for \(y\) in terms of \(x\).

Question 5:
AnswerMarks Guidance
AnswerMark Notes
Separate variables and obtain \(\int\frac{1}{y}\,dy = \int\frac{x+2}{x+1}\,dx\)B1
Obtain term \(\ln y\)B1
Use an appropriate method to integrate \((x+2)/(x+1)\)M1 *M1
Obtain integral \(x + \ln(x+1)\), or equivalent, e.g. \(\ln(x+1) + x + 1\)A1
Use \(x = 1\) and \(y = 2\) to evaluate a constant, or as limitsDM1
Obtain correct solution in \(x\) and \(y\) in any form e.g. \(\ln y = x + \ln(x+1) - 1\)A1
Obtain answer \(y = (x+1)e^{x-1}\)A1
## Question 5:
| Answer | Mark | Notes |
|--------|------|-------|
| Separate variables and obtain $\int\frac{1}{y}\,dy = \int\frac{x+2}{x+1}\,dx$ | B1 | |
| Obtain term $\ln y$ | B1 | |
| Use an appropriate method to integrate $(x+2)/(x+1)$ | M1 | *M1 |
| Obtain integral $x + \ln(x+1)$, or equivalent, e.g. $\ln(x+1) + x + 1$ | A1 | |
| Use $x = 1$ and $y = 2$ to evaluate a constant, or as limits | DM1 | |
| Obtain correct solution in $x$ and $y$ in any form e.g. $\ln y = x + \ln(x+1) - 1$ | A1 | |
| Obtain answer $y = (x+1)e^{x-1}$ | A1 | |
5 The variables $x$ and $y$ satisfy the differential equation

$$( x + 1 ) \frac { \mathrm { d } y } { \mathrm {~d} x } = y ( x + 2 )$$

and it is given that $y = 2$ when $x = 1$. Solve the differential equation and obtain an expression for $y$ in terms of $x$.\\

\hfill \mbox{\textit{CAIE P3 2017 Q5 [7]}}