Standard +0.3 This is a straightforward logarithm equation requiring manipulation of log laws (bringing terms to one side, using power and quotient rules) and solving a resulting quadratic equation. While it involves logs to base 2 rather than natural logs, the technique is standard A-level fare with no novel insight required, making it slightly easier than average.
## Question 2:
| Answer | Mark | Notes |
|--------|------|-------|
| Use law for the logarithm of a power or a quotient on the given equation | M1 | |
| Use $\log_2 8 = 3$ or $2^3 = 8$ | M1 | |
| Obtain $x^2 - 8x - 8 = 0$, or horizontal equivalent | A1 | |
| Solve a 3-term quadratic equation | M1 | |
| Obtain final answer $x = 8.90$ only | A1 | |