CAIE P3 2014 November — Question 6 8 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2014
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNumerical integration
TypeTrapezium rule with stated number of strips
DifficultyModerate -0.3 Part (i) is a routine trapezium rule application with straightforward function evaluations. Part (ii) requires binomial expansion for small x (standard P3 technique) followed by term-by-term integration. Both parts are standard textbook exercises with no novel problem-solving required, making this slightly easier than average but not trivial due to the two-part structure and algebraic manipulation needed.
Spec1.04c Extend binomial expansion: rational n, |x|<11.09f Trapezium rule: numerical integration

6 It is given that \(I = \int _ { 0 } ^ { 0.3 } \left( 1 + 3 x ^ { 2 } \right) ^ { - 2 } \mathrm {~d} x\).
  1. Use the trapezium rule with 3 intervals to find an approximation to \(I\), giving the answer correct to 3 decimal places.
  2. For small values of \(x , \left( 1 + 3 x ^ { 2 } \right) ^ { - 2 } \approx 1 + a x ^ { 2 } + b x ^ { 4 }\). Find the values of the constants \(a\) and \(b\). Hence, by evaluating \(\int _ { 0 } ^ { 0.3 } \left( 1 + a x ^ { 2 } + b x ^ { 4 } \right) \mathrm { d } x\), find a second approximation to \(I\), giving the answer correct to 3 decimal places.

(i)
AnswerMarks Guidance
State or imply correct ordinates \(1, 0.94259\ldots, 0.79719\ldots, 0.62000\ldots\)B1
Use correct formula or equivalent with \(h = 0.1\) and four \(y\) valuesM1
Obtain \(0.255\) with no errors seenA1 [3]
(ii)
AnswerMarks
Obtain or imply \(a = -6\)B1
Obtain \(x^4\) term including correct attempt at coefficientM1
Obtain or imply \(b = 27\)A1
Either
AnswerMarks
Integrate to obtain \(x - 2x^3 + \frac{27}{5}x^5\), following their values of \(a\) and \(b\)B1♦
Obtain \(0.259\)B1
Or
AnswerMarks Guidance
Use correct trapezium rule with at least 3 ordinatesM1
Obtain \(0.259\) (from 4)A1 [5]
**(i)**
State or imply correct ordinates $1, 0.94259\ldots, 0.79719\ldots, 0.62000\ldots$ | B1 |
Use correct formula or equivalent with $h = 0.1$ and four $y$ values | M1 |
Obtain $0.255$ with no errors seen | A1 | [3]

**(ii)**
Obtain or imply $a = -6$ | B1 |
Obtain $x^4$ term including correct attempt at coefficient | M1 |
Obtain or imply $b = 27$ | A1 |

**Either**
Integrate to obtain $x - 2x^3 + \frac{27}{5}x^5$, following their values of $a$ and $b$ | B1♦ |
Obtain $0.259$ | B1 |

**Or**
Use correct trapezium rule with at least 3 ordinates | M1 |
Obtain $0.259$ (from 4) | A1 | [5]
6 It is given that $I = \int _ { 0 } ^ { 0.3 } \left( 1 + 3 x ^ { 2 } \right) ^ { - 2 } \mathrm {~d} x$.\\
(i) Use the trapezium rule with 3 intervals to find an approximation to $I$, giving the answer correct to 3 decimal places.\\
(ii) For small values of $x , \left( 1 + 3 x ^ { 2 } \right) ^ { - 2 } \approx 1 + a x ^ { 2 } + b x ^ { 4 }$. Find the values of the constants $a$ and $b$. Hence, by evaluating $\int _ { 0 } ^ { 0.3 } \left( 1 + a x ^ { 2 } + b x ^ { 4 } \right) \mathrm { d } x$, find a second approximation to $I$, giving the answer correct to 3 decimal places.

\hfill \mbox{\textit{CAIE P3 2014 Q6 [8]}}