CAIE P3 2014 November — Question 3 7 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2014
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFactor & Remainder Theorem
TypeTwo factors given
DifficultyModerate -0.3 This is a straightforward application of the factor theorem requiring substitution of x=-1 and x=-2 to form simultaneous equations for part (i), then polynomial division for part (ii). While it involves multiple steps and techniques, each step is routine and follows standard procedures with no novel insight required, making it slightly easier than average.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem

3 The polynomial \(4 x ^ { 3 } + a x ^ { 2 } + b x - 2\), where \(a\) and \(b\) are constants, is denoted by \(\mathrm { p } ( x )\). It is given that \(( x + 1 )\) and \(( x + 2 )\) are factors of \(\mathrm { p } ( x )\).
  1. Find the values of \(a\) and \(b\).
  2. When \(a\) and \(b\) have these values, find the remainder when \(\mathrm { p } ( x )\) is divided by \(\left( x ^ { 2 } + 1 \right)\).

(i) Either route:
AnswerMarks
Equate \(p(-1)\) or \(p(-2)\) to zero or divide by \((x+1)\) or \((x+2)\) and equate constant remainder to zeroM*1
Obtain two equations \(a - b = 6\) and \(4a - 2b = 34\) or equivalentsA1
Solve pair of equations for \(a\) or \(b\)DM*1
Obtain \(a = 11\) and \(b = 5\)A1
Or route:
AnswerMarks Guidance
State or imply third factor is \(4x - 1\)B1
Carry out complete expansion of \((x+1)(x+2)(4x-1)\) or \((x+1)(x+2)(Cx+D)\)M1
Obtain \(a = 11\)A1
Obtain \(b = 5\)A1 [4]
(ii)
AnswerMarks Guidance
Use division or equivalent and obtaining linear remainderM1
Obtain quotient \(4x + a\), following their value of \(a\)A1♦
Indicate remainder \(x - 13\)A1 [3]
**(i) Either route:**
Equate $p(-1)$ or $p(-2)$ to zero or divide by $(x+1)$ or $(x+2)$ and equate constant remainder to zero | M*1 |
Obtain two equations $a - b = 6$ and $4a - 2b = 34$ or equivalents | A1 |
Solve pair of equations for $a$ or $b$ | DM*1 |
Obtain $a = 11$ and $b = 5$ | A1 |

**Or route:**
State or imply third factor is $4x - 1$ | B1 |
Carry out complete expansion of $(x+1)(x+2)(4x-1)$ or $(x+1)(x+2)(Cx+D)$ | M1 |
Obtain $a = 11$ | A1 |
Obtain $b = 5$ | A1 | [4]

**(ii)**
Use division or equivalent and obtaining linear remainder | M1 |
Obtain quotient $4x + a$, following their value of $a$ | A1♦ |
Indicate remainder $x - 13$ | A1 | [3]
3 The polynomial $4 x ^ { 3 } + a x ^ { 2 } + b x - 2$, where $a$ and $b$ are constants, is denoted by $\mathrm { p } ( x )$. It is given that $( x + 1 )$ and $( x + 2 )$ are factors of $\mathrm { p } ( x )$.\\
(i) Find the values of $a$ and $b$.\\
(ii) When $a$ and $b$ have these values, find the remainder when $\mathrm { p } ( x )$ is divided by $\left( x ^ { 2 } + 1 \right)$.

\hfill \mbox{\textit{CAIE P3 2014 Q3 [7]}}