Edexcel D2 — Question 4 8 marks

Exam BoardEdexcel
ModuleD2 (Decision Mathematics 2)
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTravelling Salesman
TypeNearest Neighbour Algorithm
DifficultyModerate -0.8 This is a standard algorithmic application question from D2. Part (a) requires mechanical application of nearest neighbour algorithm (selecting minimum values from table), part (b) uses the standard minimum spanning tree deletion method for lower bounds, and part (c) simply requires writing the inequality from parts (a) and (b). All procedures are routine textbook exercises with no problem-solving insight required, though the table lookup and arithmetic takes some care.
Spec7.04c Travelling salesman upper bound: nearest neighbour method7.04d Travelling salesman lower bound: using minimum spanning tree

4. The table shows the least distances, in km, between six towns \(A , B , C , D , E\) and \(F\).
\(A\)\(B\)\(C\)\(D\)\(E\)\(F\)
\(A\)-98123689671
\(B\)98-7412947120
\(C\)12374-10211163
\(D\)68129102-8559
\(E\)964711185-115
\(F\)711206359115-
  1. Starting at \(A\), and making your method clear, find an upper bound for the travelling salesman problem using the nearest neighbour algorithm.
  2. By deleting \(A\), and all of its arcs, find a lower bound for the travelling salesman problem.
  3. Write down an inequality about the length of the optimal route.

Question 4:
Part (a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(A_{68}\ D_{59}\ F_{63}\ C_{74}\ B_{47}\ E_{96}\ A\), total \(= 407\) kmM1 A1 A1(3)
Part (b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(E_{47}\ B_{74}\ C_{63}\ F_{59}\ D\) with connections via \(A\) (68, 71)M1
\(243 + 68 + 71 = 382\) kmA1 A1(3)
Part (c):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(382 <\) optimal route \(\leq 407\)M1 A1(2)
## Question 4:

### Part (a):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $A_{68}\ D_{59}\ F_{63}\ C_{74}\ B_{47}\ E_{96}\ A$, total $= 407$ km | M1 A1 A1(3) | |

### Part (b):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $E_{47}\ B_{74}\ C_{63}\ F_{59}\ D$ with connections via $A$ (68, 71) | M1 | |
| $243 + 68 + 71 = 382$ km | A1 A1(3) | |

### Part (c):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $382 <$ optimal route $\leq 407$ | M1 A1(2) | |

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4. The table shows the least distances, in km, between six towns $A , B , C , D , E$ and $F$.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | c | }
\hline
 & $A$ & $B$ & $C$ & $D$ & $E$ & $F$ \\
\hline
$A$ & - & 98 & 123 & 68 & 96 & 71 \\
\hline
$B$ & 98 & - & 74 & 129 & 47 & 120 \\
\hline
$C$ & 123 & 74 & - & 102 & 111 & 63 \\
\hline
$D$ & 68 & 129 & 102 & - & 85 & 59 \\
\hline
$E$ & 96 & 47 & 111 & 85 & - & 115 \\
\hline
$F$ & 71 & 120 & 63 & 59 & 115 & - \\
\hline
\end{tabular}
\end{center}
\begin{enumerate}[label=(\alph*)]
\item Starting at $A$, and making your method clear, find an upper bound for the travelling salesman problem using the nearest neighbour algorithm.
\item By deleting $A$, and all of its arcs, find a lower bound for the travelling salesman problem.
\item Write down an inequality about the length of the optimal route.
\end{enumerate}

\hfill \mbox{\textit{Edexcel D2  Q4 [8]}}