CAIE P3 2013 November — Question 3 5 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2013
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFactor & Remainder Theorem
TypeSingle unknown from factor condition
DifficultyModerate -0.8 Part (i) is a direct application of the factor theorem requiring substitution of x=-2 and solving a linear equation for a. Part (ii) involves factorizing the cubic and analyzing a quadratic discriminant. This is a standard textbook exercise with routine techniques and no novel problem-solving required, making it easier than average.
Spec1.02d Quadratic functions: graphs and discriminant conditions1.02j Manipulate polynomials: expanding, factorising, division, factor theorem

3 The polynomial \(\mathrm { f } ( x )\) is defined by $$f ( x ) = x ^ { 3 } + a x ^ { 2 } - a x + 14$$ where \(a\) is a constant. It is given that ( \(x + 2\) ) is a factor of \(\mathrm { f } ( x )\).
  1. Find the value of \(a\).
  2. Show that, when \(a\) has this value, the equation \(\mathrm { f } ( x ) = 0\) has only one real root.

AnswerMarks Guidance
(i) Substitute \(-2\) and equate to zero or divide by \(x + 2\) and equate remainder to zero or use \(-2\) in synthetic divisionM1
Obtain \(a = -1\)A1 [2]
(ii) Attempt to find quadratic factor by division reaching \(x^2 + kx\), or inspection as far as \((x+2)(x^2 + Bx + c)\) and equations for one or both of \(B\) and \(C\), or \((x+2)(Ax^2 + Bx + 7)\) and equations for one or both of \(A\) and \(B\)M1
Obtain \(x^2 - 3x + 7\)A1
Use discriminant to obtain \(-19\), or equivalent, and confirm one rootA1 cwo [3]
**(i)** Substitute $-2$ and equate to zero or divide by $x + 2$ and equate remainder to zero or use $-2$ in synthetic division | M1 |
Obtain $a = -1$ | A1 | [2]

**(ii)** Attempt to find quadratic factor by division reaching $x^2 + kx$, or inspection as far as $(x+2)(x^2 + Bx + c)$ and equations for one or both of $B$ and $C$, or $(x+2)(Ax^2 + Bx + 7)$ and equations for one or both of $A$ and $B$ | M1 |
Obtain $x^2 - 3x + 7$ | A1 |
Use discriminant to obtain $-19$, or equivalent, and **confirm one root** | A1 cwo | [3]
3 The polynomial $\mathrm { f } ( x )$ is defined by

$$f ( x ) = x ^ { 3 } + a x ^ { 2 } - a x + 14$$

where $a$ is a constant. It is given that ( $x + 2$ ) is a factor of $\mathrm { f } ( x )$.\\
(i) Find the value of $a$.\\
(ii) Show that, when $a$ has this value, the equation $\mathrm { f } ( x ) = 0$ has only one real root.

\hfill \mbox{\textit{CAIE P3 2013 Q3 [5]}}