CAIE P3 2013 November — Question 6 9 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2013
SessionNovember
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors: Lines & Planes
TypeLine of intersection of planes
DifficultyStandard +0.3 This is a standard two-part question on planes requiring routine application of formulas: (i) finding angle between planes using dot product of normal vectors, and (ii) finding line of intersection by solving simultaneous equations and expressing parametrically. Both are textbook procedures with no novel insight required, making it slightly easier than average.
Spec4.04d Angles: between planes and between line and plane4.04e Line intersections: parallel, skew, or intersecting

6 Two planes have equations \(3 x - y + 2 z = 9\) and \(x + y - 4 z = - 1\).
  1. Find the acute angle between the planes.
  2. Find a vector equation of the line of intersection of the planes.

AnswerMarks Guidance
(i) Find scalar product of the normals to the planesM1
Using the correct process for the moduli, divide the scalar product by the product of the moduli and find \(\cos^{-1}\) of the resultM1
Obtain \(67.8°\) (or \(1.18\) radians)A1 [3]
(ii) EITHER Carry out complete method for finding point on lineM1
Obtain one such point, e.g. \((2, -3, 0)\) or \(\left(-\frac{17}{7}, 0, \frac{6}{7}\right)\) or \((0, -17, -4)\) or \(\ldots\)A1...
Either State \(3a - b + 2c = 0\) and \(a + b - 4c = 0\) or equivalentB1
Attempt to solve for one ratio, e.g. \(a : b\)M1
Obtain \(a : b : c = 1 : 7 : 2\) or equivalentA1
State a correct final answer, e.g. \(\mathbf{r} = [2, -3, 0] + \lambda[1, 7, 2]\)A1✱
Or 1 Obtain a second point on the lineA1
Subtract position vectors to obtain direction vectorM1
Obtain \([1, 7, 2]\) or equivalentA1
State a correct final answer, e.g. \(\mathbf{r} = [2, -3, 0] + \lambda[1, 7, 2]\)A1✱
Or 2 Use correct method to calculate vector product of two normalsM1
Obtain two correct componentsA1
Obtain \([2, 14, 4]\) or equivalentA1
State a correct final answer, e.g. \(\mathbf{r} = [2, -3, 0] + \lambda[1, 7, 2]\)A1✱
[✱ is dependent on both M marks in all three cases]
OR 3 Express one variable in terms of a second variableM1
Obtain a correct simplified expression, e.g. \(x = \frac{1}{2}(4+z)\)A1
Express the first variable in terms of third variableM1
Obtain a correct simplified expression, e.g. \(x = \frac{1}{7}(17+y)\)A1
Form a vector equation for the lineM1
State a correct final answer, e.g. \(\mathbf{r} = [0, -17, -4] + \lambda[1, 7, 2]\)A1
OR 4 Express one variable in terms of a second variableM1
Obtain a correct simplified expression, e.g. \(z = 2x - 4\)A1
Express third variable in terms of the second variableM1
Obtain a correct simplified expression, e.g. \(y = 7x - 17\)A1
Form a vector equation for the lineM1
State a correct final answer, e.g. \(\mathbf{r} = [0, -17, -4] + \lambda[1, 7, 2]\)A1 [6]
**(i)** Find scalar product of the normals to the planes | M1 |
Using the correct process for the moduli, divide the scalar product by the product of the moduli and find $\cos^{-1}$ of the result | M1 |
Obtain $67.8°$ (or $1.18$ radians) | A1 | [3]

**(ii)** **EITHER** Carry out complete method for finding point on line | M1 |
Obtain one such point, e.g. $(2, -3, 0)$ or $\left(-\frac{17}{7}, 0, \frac{6}{7}\right)$ or $(0, -17, -4)$ or $\ldots$ | A1... |
**Either** State $3a - b + 2c = 0$ and $a + b - 4c = 0$ or equivalent | B1 |
Attempt to solve for one ratio, e.g. $a : b$ | M1 |
Obtain $a : b : c = 1 : 7 : 2$ or equivalent | A1 |
State a correct final answer, e.g. $\mathbf{r} = [2, -3, 0] + \lambda[1, 7, 2]$ | A1✱ |
**Or 1** Obtain a second point on the line | A1 |
Subtract position vectors to obtain direction vector | M1 |
Obtain $[1, 7, 2]$ or equivalent | A1 |
State a correct final answer, e.g. $\mathbf{r} = [2, -3, 0] + \lambda[1, 7, 2]$ | A1✱ |
**Or 2** Use correct method to calculate vector product of two normals | M1 |
Obtain two correct components | A1 |
Obtain $[2, 14, 4]$ or equivalent | A1 |
State a correct final answer, e.g. $\mathbf{r} = [2, -3, 0] + \lambda[1, 7, 2]$ | A1✱ |
[✱ is dependent on both M marks in all three cases] |
**OR 3** Express one variable in terms of a second variable | M1 |
Obtain a correct simplified expression, e.g. $x = \frac{1}{2}(4+z)$ | A1 |
Express the first variable in terms of third variable | M1 |
Obtain a correct simplified expression, e.g. $x = \frac{1}{7}(17+y)$ | A1 |
Form a vector equation for the line | M1 |
State a correct final answer, e.g. $\mathbf{r} = [0, -17, -4] + \lambda[1, 7, 2]$ | A1 |
**OR 4** Express one variable in terms of a second variable | M1 |
Obtain a correct simplified expression, e.g. $z = 2x - 4$ | A1 |
Express third variable in terms of the second variable | M1 |
Obtain a correct simplified expression, e.g. $y = 7x - 17$ | A1 |
Form a vector equation for the line | M1 |
State a correct final answer, e.g. $\mathbf{r} = [0, -17, -4] + \lambda[1, 7, 2]$ | A1 | [6]
6 Two planes have equations $3 x - y + 2 z = 9$ and $x + y - 4 z = - 1$.\\
(i) Find the acute angle between the planes.\\
(ii) Find a vector equation of the line of intersection of the planes.

\hfill \mbox{\textit{CAIE P3 2013 Q6 [9]}}