AQA D2 2011 January — Question 1 14 marks

Exam BoardAQA
ModuleD2 (Decision Mathematics 2)
Year2011
SessionJanuary
Marks14
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCritical Path Analysis
TypeCalculate early and late times
DifficultyModerate -0.5 This is a standard Critical Path Analysis question requiring systematic application of the forward and backward pass algorithms to find early/late times, identify the critical path, calculate float, and construct resource histograms. While it involves multiple parts and careful bookkeeping, it follows routine D2 procedures without requiring novel problem-solving insights or complex reasoning beyond the standard algorithm.
Spec7.05a Critical path analysis: activity on arc networks7.05b Forward and backward pass: earliest/latest times, critical activities7.05c Total float: calculation and interpretation7.05d Latest start and earliest finish: independent and interfering float

1
A group of workers is involved in a decorating project. The table shows the activities involved. Each worker can perform any of the given activities.
ActivityA\(B\)CD\(E\)\(F\)GHI\(J\)\(K\)\(L\)
Duration (days)256794323231
Number of workers required635252445324
The activity network for the project is given in Figure 1 below.
  1. Find the earliest start time and the latest finish time for each activity, inserting their values on Figure 1.
  2. Hence find:
    1. the critical path;
    2. the float time for activity \(D\).
      1. \begin{figure}[h]
        \captionsetup{labelformat=empty} \caption{Figure 1} \includegraphics[alt={},max width=\textwidth]{172c5c92-4254-4593-b741-1caa83a1e833-02_647_1657_1640_180}
        \end{figure}
        1. The critical path is \(\_\_\_\_\)
        2. The float time for activity \(D\) is \(\_\_\_\_\)
    3. Given that each activity starts as early as possible and assuming that there is no limit to the number of workers available, draw a resource histogram for the project on Figure 2 below, indicating clearly which activities are taking place at any given time.
    4. It is later discovered that there are only 8 workers available at any time. Use resource levelling to construct a new resource histogram on Figure 3 below, showing how the project can be completed with the minimum extra time. State the minimum extra time required.
    5. \begin{figure}[h]
      \captionsetup{labelformat=empty} \caption{Figure 2} \includegraphics[alt={},max width=\textwidth]{172c5c92-4254-4593-b741-1caa83a1e833-03_586_1708_922_150}
      \end{figure}
    6. \begin{figure}[h]
      \captionsetup{labelformat=empty} \caption{Figure 3} \includegraphics[alt={},max width=\textwidth]{172c5c92-4254-4593-b741-1caa83a1e833-03_496_1705_1672_153}
      \end{figure} The minimum extra time required is \(\_\_\_\_\)

Question 1:
Part (a) - Earliest Start Times and Latest Finish Times
AnswerMarks Guidance
AnswerMark Guidance
Earliest start times: \(A=0, B=2, C=2, D=2, E=7, F=7, G=11, H=14, I=14, J=16, K=17, L=19\)B1 Forward pass correct
Latest finish times: \(L=20, J=19, K=20, H=17, I=20, G=14, E=16, F=18, B=7, C=8, D=18, A=2\)B1 Backward pass correct
Critical path length = 20 daysB1
All values correctly placed on diagramB1
Part (b)(i) - Critical Path
AnswerMarks Guidance
AnswerMark Guidance
\(A \to C \to E \to G \to H \to J \to L\)B2 B1 for partially correct path
Part (b)(ii) - Float time for activity D
AnswerMarks Guidance
AnswerMark Guidance
Float \(= \) latest finish time \(-\) duration \(-\) earliest start timeM1 Correct method shown
\(= 18 - 7 - 2 = 9\) daysA1
# Question 1:

## Part (a) - Earliest Start Times and Latest Finish Times

| Answer | Mark | Guidance |
|--------|------|----------|
| Earliest start times: $A=0, B=2, C=2, D=2, E=7, F=7, G=11, H=14, I=14, J=16, K=17, L=19$ | B1 | Forward pass correct |
| Latest finish times: $L=20, J=19, K=20, H=17, I=20, G=14, E=16, F=18, B=7, C=8, D=18, A=2$ | B1 | Backward pass correct |
| Critical path length = 20 days | B1 | |
| All values correctly placed on diagram | B1 | |

## Part (b)(i) - Critical Path

| Answer | Mark | Guidance |
|--------|------|----------|
| $A \to C \to E \to G \to H \to J \to L$ | B2 | B1 for partially correct path |

## Part (b)(ii) - Float time for activity D

| Answer | Mark | Guidance |
|--------|------|----------|
| Float $= $ latest finish time $-$ duration $-$ earliest start time | M1 | Correct method shown |
| $= 18 - 7 - 2 = 9$ days | A1 | |

---
1\\
A group of workers is involved in a decorating project. The table shows the activities involved. Each worker can perform any of the given activities.

\begin{center}
\begin{tabular}{|l|l|l|l|l|l|l|l|l|l|l|l|l|}
\hline
Activity & A & $B$ & C & D & $E$ & $F$ & G & H & I & $J$ & $K$ & $L$ \\
\hline
Duration (days) & 2 & 5 & 6 & 7 & 9 & 4 & 3 & 2 & 3 & 2 & 3 & 1 \\
\hline
Number of workers required & 6 & 3 & 5 & 2 & 5 & 2 & 4 & 4 & 5 & 3 & 2 & 4 \\
\hline
\end{tabular}
\end{center}

The activity network for the project is given in Figure 1 below.
\begin{enumerate}[label=(\alph*)]
\item Find the earliest start time and the latest finish time for each activity, inserting their values on Figure 1.
\item Hence find:
\begin{enumerate}[label=(\roman*)]
\item the critical path;
\item the float time for activity $D$.\\
(a)

\begin{figure}[h]
\begin{center}
\captionsetup{labelformat=empty}
\caption{Figure 1}
  \includegraphics[alt={},max width=\textwidth]{172c5c92-4254-4593-b741-1caa83a1e833-02_647_1657_1640_180}
\end{center}
\end{figure}

(b) (i) The critical path is $\_\_\_\_$\\
(ii) The float time for activity $D$ is $\_\_\_\_$
\end{enumerate}\item Given that each activity starts as early as possible and assuming that there is no limit to the number of workers available, draw a resource histogram for the project on Figure 2 below, indicating clearly which activities are taking place at any given time.
\item It is later discovered that there are only 8 workers available at any time. Use resource levelling to construct a new resource histogram on Figure 3 below, showing how the project can be completed with the minimum extra time. State the minimum extra time required.\\
(c)

\begin{figure}[h]
\begin{center}
\captionsetup{labelformat=empty}
\caption{Figure 2}
  \includegraphics[alt={},max width=\textwidth]{172c5c92-4254-4593-b741-1caa83a1e833-03_586_1708_922_150}
\end{center}
\end{figure}

(d)

\begin{figure}[h]
\begin{center}
\captionsetup{labelformat=empty}
\caption{Figure 3}
  \includegraphics[alt={},max width=\textwidth]{172c5c92-4254-4593-b741-1caa83a1e833-03_496_1705_1672_153}
\end{center}
\end{figure}

The minimum extra time required is $\_\_\_\_$
\end{enumerate}

\hfill \mbox{\textit{AQA D2 2011 Q1 [14]}}