AQA FP3 2010 June — Question 5 13 marks

Exam BoardAQA
ModuleFP3 (Further Pure Mathematics 3)
Year2010
SessionJune
Marks13
PaperDownload PDF ↗
TopicTaylor series
TypeMaclaurin series for ln(exponential expressions)
DifficultyStandard +0.8 This is a multi-part Further Maths question requiring Maclaurin series manipulation, successive differentiation of composite functions (ln and exponential), and L'Hôpital's rule application. Part (b) involves careful algebraic manipulation of derivatives, and part (c) requires combining both series to evaluate a limit—all standard FP3 techniques but requiring precision and multiple steps, placing it moderately above average difficulty.
Spec1.06d Natural logarithm: ln(x) function and properties1.07l Derivative of ln(x): and related functions4.08a Maclaurin series: find series for function4.08b Standard Maclaurin series: e^x, sin, cos, ln(1+x), (1+x)^n

5
  1. Write down the expansion of \(\cos 4 x\) in ascending powers of \(x\) up to and including the term in \(x ^ { 4 }\). Give your answer in its simplest form.
    1. Given that \(y = \ln \left( 2 - \mathrm { e } ^ { x } \right)\), find \(\frac { \mathrm { d } y } { \mathrm {~d} x } , \frac { \mathrm {~d} ^ { 2 } y } { \mathrm {~d} x ^ { 2 } }\) and \(\frac { \mathrm { d } ^ { 3 } y } { \mathrm {~d} x ^ { 3 } }\).
      (You may leave your expression for \(\frac { \mathrm { d } ^ { 3 } y } { \mathrm {~d} x ^ { 3 } }\) unsimplified.)
    2. Hence, by using Maclaurin's theorem, show that the first three non-zero terms in the expansion, in ascending powers of \(x\), of \(\ln \left( 2 - \mathrm { e } ^ { x } \right)\) are $$- x - x ^ { 2 } - x ^ { 3 }$$
  2. Find $$\lim _ { x \rightarrow 0 } \left[ \frac { x \ln \left( 2 - \mathrm { e } ^ { x } \right) } { 1 - \cos 4 x } \right]$$

5
\begin{enumerate}[label=(\alph*)]
\item Write down the expansion of $\cos 4 x$ in ascending powers of $x$ up to and including the term in $x ^ { 4 }$. Give your answer in its simplest form.
\item \begin{enumerate}[label=(\roman*)]
\item Given that $y = \ln \left( 2 - \mathrm { e } ^ { x } \right)$, find $\frac { \mathrm { d } y } { \mathrm {~d} x } , \frac { \mathrm {~d} ^ { 2 } y } { \mathrm {~d} x ^ { 2 } }$ and $\frac { \mathrm { d } ^ { 3 } y } { \mathrm {~d} x ^ { 3 } }$.\\
(You may leave your expression for $\frac { \mathrm { d } ^ { 3 } y } { \mathrm {~d} x ^ { 3 } }$ unsimplified.)
\item Hence, by using Maclaurin's theorem, show that the first three non-zero terms in the expansion, in ascending powers of $x$, of $\ln \left( 2 - \mathrm { e } ^ { x } \right)$ are

$$- x - x ^ { 2 } - x ^ { 3 }$$
\end{enumerate}\item Find

$$\lim _ { x \rightarrow 0 } \left[ \frac { x \ln \left( 2 - \mathrm { e } ^ { x } \right) } { 1 - \cos 4 x } \right]$$
\end{enumerate}

\hfill \mbox{\textit{AQA FP3 2010 Q5 [13]}}