| Exam Board | CAIE |
|---|---|
| Module | FP2 (Further Pure Mathematics 2) |
| Year | 2019 |
| Session | June |
| Paper | Download PDF ↗ |
| Topic | Simple Harmonic Motion |
| Type | Energy methods in SHM |
| Difficulty | Challenging +1.2 This is a standard Further Maths SHM energy problem requiring Hooke's law, energy conservation, and SHM period formulas. Part (i) is straightforward energy bookkeeping, part (ii) uses standard F=-kx to establish SHM, and part (iii) requires finding when KE = 0.75(initial KE) using energy methods and inverse trig. While multi-step, all techniques are routine for FM students with no novel insight required. |
| Spec | 4.10f Simple harmonic motion: x'' = -omega^2 x6.02i Conservation of energy: mechanical energy principle |
A light spring has natural length $a$ and modulus of elasticity $k m g$. The spring lies on a smooth horizontal surface with one end attached to a fixed point $O$. A particle $P$ of mass $m$ is attached to the other end of the spring. The system is in equilibrium with $O P = a$. The particle is projected towards $O$ with speed $u$ and comes to instantaneous rest when $O P = \frac { 3 } { 4 } a$.\\
(i) Use an energy method to show that $k = \frac { 16 u ^ { 2 } } { a g }$.\\
(ii) Show that $P$ performs simple harmonic motion and find the period of this motion, giving your answer in terms of $u$ and $a$.\\
(iii) Find, in terms of $u$ and $a$, the time that elapses before $P$ first loses $25 \%$ of its initial kinetic energy.\\
\hfill \mbox{\textit{CAIE FP2 2019 Q11 EITHER}}