CAIE FP2 2019 June — Question 9 10 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2019
SessionJune
Marks10
PaperDownload PDF ↗
TopicT-tests (unknown variance)
TypeSingle sample confidence interval t-distribution
DifficultyStandard +0.3 This is a straightforward one-sample t-test with clearly stated hypotheses and standard confidence interval calculation. Students must calculate sample mean and variance from summary statistics, then apply routine t-test procedures. While it requires multiple steps and careful calculation, it follows a standard template with no conceptual surprises, making it slightly easier than average for Further Maths statistics.
Spec5.05c Hypothesis test: normal distribution for population mean

9 A farmer grows large amounts of a certain crop. On average, the yield per plant has been 0.75 kg . The farmer has improved the soil in which the crop grows, and she claims that the yield per plant has increased. A random sample of 10 plants grown in the improved soil is chosen. The yields, \(x \mathrm {~kg}\), are summarised as follows. $$\Sigma x = 7.85 \quad \Sigma x ^ { 2 } = 6.19$$
  1. Test at the \(5 \%\) significance level whether the farmer's claim is justified, assuming a normal distribution.
  2. Find a 95\% confidence interval for the population mean yield for plants grown in the new soil.

9 A farmer grows large amounts of a certain crop. On average, the yield per plant has been 0.75 kg . The farmer has improved the soil in which the crop grows, and she claims that the yield per plant has increased. A random sample of 10 plants grown in the improved soil is chosen. The yields, $x \mathrm {~kg}$, are summarised as follows.

$$\Sigma x = 7.85 \quad \Sigma x ^ { 2 } = 6.19$$

(i) Test at the $5 \%$ significance level whether the farmer's claim is justified, assuming a normal distribution.\\

(ii) Find a 95\% confidence interval for the population mean yield for plants grown in the new soil.\\

\hfill \mbox{\textit{CAIE FP2 2019 Q9 [10]}}