| Exam Board | CAIE |
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| Module | P3 (Pure Mathematics 3) |
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| Year | 2005 |
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| Session | November |
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| Topic | Harmonic Form |
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5 By expressing \(8 \sin \theta - 6 \cos \theta\) in the form \(R \sin ( \theta - \alpha )\), solve the equation
$$8 \sin \theta - 6 \cos \theta = 7$$
for \(0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }\).