CAIE P3 2005 November — Question 1 4 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2005
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModulus function
TypeSolve |linear| > |linear|
DifficultyStandard +0.3 This requires understanding modulus inequalities and systematic case analysis by considering critical points at x=a and x=3a. While it involves multiple cases, the algebraic manipulation within each case is straightforward, making it slightly above average difficulty but still a standard textbook exercise for P3 level.
Spec1.02l Modulus function: notation, relations, equations and inequalities

1 Given that \(a\) is a positive constant, solve the inequality $$| x - 3 a | > | x - a |$$

EITHER:
AnswerMarks
Expand and solve the inequality, or equivalentM1
Obtain critical value \(2a\)A1
State correct answer \(x < 2a\) onlyA1
State non-modular inequality \((x-3a)^2 > (x-a)^2\), or corresponding equationB1
OR:
AnswerMarks
State a correct linear equation for the critical value, e.g. \(-3a = -(x-a)\), or corresponding inequalityB1
Solve the linear equation for \(x\), or equivalentM1
Obtain critical value \(2a\)A1
State correct answer \(x < 2a\) onlyA1
OR:
AnswerMarks Guidance
Make recognizable sketches of both \(y =x - 3a \) and \(y =
Obtain a critical value from the intersection of the graphsM1
Obtain critical value \(2a\)A1
Obtain correct answer \(x < 2a\) onlyA1
Total: [4]
**EITHER:**
Expand and solve the inequality, or equivalent | M1 |
Obtain critical value $2a$ | A1 |
State correct answer $x < 2a$ only | A1 |
State non-modular inequality $(x-3a)^2 > (x-a)^2$, or corresponding equation | B1 |

**OR:**
State a correct linear equation for the critical value, e.g. $-3a = -(x-a)$, or corresponding inequality | B1 |
Solve the linear equation for $x$, or equivalent | M1 |
Obtain critical value $2a$ | A1 |
State correct answer $x < 2a$ only | A1 |

**OR:**
Make recognizable sketches of both $y = |x - 3a|$ and $y = |x - a|$ on a single diagram | B1 |
Obtain a critical value from the intersection of the graphs | M1 |
Obtain critical value $2a$ | A1 |
Obtain correct answer $x < 2a$ only | A1 |

**Total: [4]**

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1 Given that $a$ is a positive constant, solve the inequality

$$| x - 3 a | > | x - a |$$

\hfill \mbox{\textit{CAIE P3 2005 Q1 [4]}}