CAIE FP2 2015 June — Question 11 EITHER

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2015
SessionJune
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments of inertia
TypeComposite body MI calculation
DifficultyHard +2.3 This is a challenging Further Maths mechanics problem requiring: (1) calculation of moment of inertia for a composite system using parallel axis theorem, (2) application of perpendicular axis theorem or parallel axis theorem again for a different axis, and (3) energy conservation with rotational motion involving a non-trivial geometry where the angle is given implicitly. The multi-stage nature, the composite object with multiple components, and the final energy equation with careful geometric analysis place this well above average difficulty.
Spec6.02i Conservation of energy: mechanical energy principle6.04d Integration: for centre of mass of laminas/solids

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A uniform disc, with centre \(O\) and radius \(a\), is surrounded by a uniform concentric ring with radius \(3 a\). The ring is rigidly attached to the rim of the disc by four symmetrically positioned uniform rods, each of mass \(\frac { 3 } { 2 } m\) and length \(2 a\). The disc and the ring each have mass \(2 m\). The rods meet the ring at the points \(A , B , C\) and \(D\). The disc, the ring and the rods are all in the same plane (see diagram). Show that the moment of inertia of this object about an axis through \(O\) perpendicular to the plane of the object is \(45 m a ^ { 2 }\). Find the moment of inertia of the object about an axis \(l\) through \(A\) in the plane of the object and tangential to the ring. A particle of mass \(3 m\) is now attached to the object at \(C\). The object, including the additional particle, is suspended from the point \(A\) and hangs in equilibrium. It is free to rotate about the axis \(l\). The centre of the disc is given a horizontal speed \(u\). When, in the subsequent motion, the object comes to instantaneous rest, \(C\) is below the level of \(A\) and \(A C\) makes an angle \(\sin ^ { - 1 } \left( \frac { 1 } { 4 } \right)\) with the horizontal. Find \(u\) in terms of \(a\) and \(g\).

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A uniform disc, with centre $O$ and radius $a$, is surrounded by a uniform concentric ring with radius $3 a$. The ring is rigidly attached to the rim of the disc by four symmetrically positioned uniform rods, each of mass $\frac { 3 } { 2 } m$ and length $2 a$. The disc and the ring each have mass $2 m$. The rods meet the ring at the points $A , B , C$ and $D$. The disc, the ring and the rods are all in the same plane (see diagram). Show that the moment of inertia of this object about an axis through $O$ perpendicular to the plane of the object is $45 m a ^ { 2 }$.

Find the moment of inertia of the object about an axis $l$ through $A$ in the plane of the object and tangential to the ring.

A particle of mass $3 m$ is now attached to the object at $C$. The object, including the additional particle, is suspended from the point $A$ and hangs in equilibrium. It is free to rotate about the axis $l$. The centre of the disc is given a horizontal speed $u$. When, in the subsequent motion, the object comes to instantaneous rest, $C$ is below the level of $A$ and $A C$ makes an angle $\sin ^ { - 1 } \left( \frac { 1 } { 4 } \right)$ with the horizontal. Find $u$ in terms of $a$ and $g$.

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