CAIE FP2 2013 June — Question 4 12 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2013
SessionJune
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments of inertia
TypeFind unknown parameter from period
DifficultyChallenging +1.8 This is a challenging Further Maths mechanics problem requiring calculation of moment of inertia for a composite system (rod, spherical shell, and ring) using parallel axis theorem, followed by applying small oscillations theory. It demands careful geometric reasoning to locate centers of mass, knowledge of standard moments of inertia, and multi-step algebraic manipulation. However, the structure is relatively standard for FP2/FM mechanics with clear guidance ('show that') for the first part.
Spec6.04d Integration: for centre of mass of laminas/solids6.05a Angular velocity: definitions

4 \includegraphics[max width=\textwidth, alt={}, center]{a473cbb8-877f-48df-8751-c76d96396734-3_906_1538_248_301} The end \(A\) of a uniform \(\operatorname { rod } A B\), of mass \(4 m\) and length \(3 a\), is rigidly attached to a point on a uniform spherical shell, of mass \(\lambda m\) and radius \(3 a\). The end \(B\) of the rod is rigidly attached to a point on a uniform ring. The ring has centre \(O\), mass \(4 m\) and radius \(\frac { 1 } { 2 } a\). The ring and the rod are in the same vertical plane. The line \(O B A\), extended, passes through the centre of the spherical shell. \(B C\) is a diameter of the ring (see diagram). Show that the moment of inertia of this system, about a fixed horizontal axis through \(C\) perpendicular to the plane of the ring, is \(( 30 + 55 \lambda ) m a ^ { 2 }\). Given that the system performs small oscillations of period \(2 \pi \sqrt { } \left( \frac { 5 a } { g } \right)\) about this axis, find the value of \(\lambda\).

Question 4:
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(I_{\text{Sphere}} = \frac{2}{3}\lambda m(3a)^2 + \lambda m(7a)^2\)M1 A1 MI of sphere about \(C\)
\(I_{\text{Rod}} = \frac{1}{3}4m(3a/2)^2 + 4m(5a/2)^2\)M1 A1 MI of rod about \(C\)
\(I_{\text{Ring}} = 4m(\frac{1}{2}a)^2 + 4m(\frac{1}{2}a)^2\)M1 MI of ring about \(C\)
\(I = (55\lambda + 28 + 2)ma^2 = (30 + 55\lambda)ma^2\) A.G.A1 Combine to give MI of system
\(Id^2\theta/dt^2 = -(\lambda\times 7 + 4\times 5/2 + 4\times\frac{1}{2})mga\sin\theta\)M1 A1 Equation of motion for system
\(\omega^2 = (12 + 7\lambda)g/(30 + 55\lambda)a\)M1 A1 Approximate \(\sin\theta \approx \theta\), find \(\omega^2\) in SHM
\(5(12 + 7\lambda) = 30 + 55\lambda\); \(\lambda = 3/2\)M1 A1 Equate \(\omega^2\) to \(4\pi^2/T^2\) to find \(\lambda\)
Total: 12 marks (6 + 6)
## Question 4:

| Answer/Working | Mark | Guidance |
|---|---|---|
| $I_{\text{Sphere}} = \frac{2}{3}\lambda m(3a)^2 + \lambda m(7a)^2$ | M1 A1 | MI of sphere about $C$ |
| $I_{\text{Rod}} = \frac{1}{3}4m(3a/2)^2 + 4m(5a/2)^2$ | M1 A1 | MI of rod about $C$ |
| $I_{\text{Ring}} = 4m(\frac{1}{2}a)^2 + 4m(\frac{1}{2}a)^2$ | M1 | MI of ring about $C$ |
| $I = (55\lambda + 28 + 2)ma^2 = (30 + 55\lambda)ma^2$ **A.G.** | A1 | Combine to give MI of system |
| $Id^2\theta/dt^2 = -(\lambda\times 7 + 4\times 5/2 + 4\times\frac{1}{2})mga\sin\theta$ | M1 A1 | Equation of motion for system |
| $\omega^2 = (12 + 7\lambda)g/(30 + 55\lambda)a$ | M1 A1 | Approximate $\sin\theta \approx \theta$, find $\omega^2$ in SHM |
| $5(12 + 7\lambda) = 30 + 55\lambda$; $\lambda = 3/2$ | M1 A1 | Equate $\omega^2$ to $4\pi^2/T^2$ to find $\lambda$ |

**Total: 12 marks (6 + 6)**

---
4\\
\includegraphics[max width=\textwidth, alt={}, center]{a473cbb8-877f-48df-8751-c76d96396734-3_906_1538_248_301}

The end $A$ of a uniform $\operatorname { rod } A B$, of mass $4 m$ and length $3 a$, is rigidly attached to a point on a uniform spherical shell, of mass $\lambda m$ and radius $3 a$. The end $B$ of the rod is rigidly attached to a point on a uniform ring. The ring has centre $O$, mass $4 m$ and radius $\frac { 1 } { 2 } a$. The ring and the rod are in the same vertical plane. The line $O B A$, extended, passes through the centre of the spherical shell. $B C$ is a diameter of the ring (see diagram). Show that the moment of inertia of this system, about a fixed horizontal axis through $C$ perpendicular to the plane of the ring, is $( 30 + 55 \lambda ) m a ^ { 2 }$.

Given that the system performs small oscillations of period $2 \pi \sqrt { } \left( \frac { 5 a } { g } \right)$ about this axis, find the value of $\lambda$.

\hfill \mbox{\textit{CAIE FP2 2013 Q4 [12]}}
This paper (2 questions)
View full paper