CAIE FP1 2014 November — Question 3 7 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2014
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProof by induction
TypeSuggest and prove formula
DifficultyStandard +0.8 This is a 'suggest and prove' induction question requiring students to spot the pattern S_n = (n+1)! - 1 from numerical examples, then prove it. While the induction proof itself is straightforward once the formula is conjectured, the pattern recognition step and working with factorials adds moderate difficulty beyond standard induction exercises. This is typical Further Maths content but not exceptionally challenging.
Spec4.01a Mathematical induction: construct proofs4.06a Summation formulae: sum of r, r^2, r^3

3 It is given that \(u _ { r } = r \times r !\) for \(r = 1,2,3 , \ldots\). Let \(S _ { n } = u _ { 1 } + u _ { 2 } + u _ { 3 } + \ldots + u _ { n }\). Write down the values of $$2 ! - S _ { 1 } , \quad 3 ! - S _ { 2 } , \quad 4 ! - S _ { 3 } , \quad 5 ! - S _ { 4 }$$ Conjecture a formula for \(S _ { n }\). Prove, by mathematical induction, a formula for \(S _ { n }\), for all positive integers \(n\).

Question 3:
AnswerMarks Guidance
Working/AnswerMarks Guidance
\(2!-S_1=1,\; 3!-S_2=1,\; 4!-S_3=1,\; 5!-S_4=1\)B2,1,0 (2) Two correct B1, all four correct B2
\(S_n=(n+1)!-1\)B1 (1)
\(2!-1=2-1=1 \Rightarrow H_1\) is trueB1
\(H_k:\; S_k=(k+1)!-1\)B1
\((k+1)!-1+(k+1)\times(k+1)!\)
\(=(k+1)!(1+k+1)-1\)M1
\(=([k+1]+1)!-1\quad\) Hence \(H_k\Rightarrow H_{k+1}\)A1 (4)
So result holds for all positive integers (by PMI).
## Question 3:

| Working/Answer | Marks | Guidance |
|---|---|---|
| $2!-S_1=1,\; 3!-S_2=1,\; 4!-S_3=1,\; 5!-S_4=1$ | B2,1,0 (2) | Two correct B1, all four correct B2 |
| $S_n=(n+1)!-1$ | B1 (1) | |
| $2!-1=2-1=1 \Rightarrow H_1$ is true | B1 | |
| $H_k:\; S_k=(k+1)!-1$ | B1 | |
| $(k+1)!-1+(k+1)\times(k+1)!$ | | |
| $=(k+1)!(1+k+1)-1$ | M1 | |
| $=([k+1]+1)!-1\quad$ Hence $H_k\Rightarrow H_{k+1}$ | A1 (4) | |
| So result holds for all positive integers (by PMI). | | |

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3 It is given that $u _ { r } = r \times r !$ for $r = 1,2,3 , \ldots$. Let $S _ { n } = u _ { 1 } + u _ { 2 } + u _ { 3 } + \ldots + u _ { n }$. Write down the values of

$$2 ! - S _ { 1 } , \quad 3 ! - S _ { 2 } , \quad 4 ! - S _ { 3 } , \quad 5 ! - S _ { 4 }$$

Conjecture a formula for $S _ { n }$.

Prove, by mathematical induction, a formula for $S _ { n }$, for all positive integers $n$.

\hfill \mbox{\textit{CAIE FP1 2014 Q3 [7]}}