CAIE P3 2019 June — Question 6 8 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2019
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeRearrange to iterative form
DifficultyStandard +0.3 This is a straightforward fixed-point iteration question requiring: (i) testing integer values to find a root, (ii) algebraic rearrangement of a polynomial equation, and (iii) applying a given iterative formula. All steps are routine and mechanical with no novel problem-solving required, making it slightly easier than average.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

6 \includegraphics[max width=\textwidth, alt={}, center]{87392b1c-3683-45b4-8d55-36760b5f0cc1-10_547_531_260_806} The diagram shows the curve \(y = x ^ { 4 } - 2 x ^ { 3 } - 7 x - 6\). The curve intersects the \(x\)-axis at the points \(( a , 0 )\) and \(( b , 0 )\), where \(a < b\). It is given that \(b\) is an integer.
  1. Find the value of \(b\).
  2. Hence show that \(a\) satisfies the equation \(a = - \frac { 1 } { 3 } \left( 2 + a ^ { 2 } + a ^ { 3 } \right)\).
  3. Use an iterative formula based on the equation in part (ii) to determine \(a\) correct to 3 decimal places. Give the result of each iteration to 5 decimal places.

Question 6(i):
AnswerMarks Guidance
AnswerMark Guidance
State \(b = 3\)B1
Total: 1
Question 6(ii):
AnswerMarks Guidance
AnswerMark Guidance
Commence division by \(x - b\) and reach partial quotient \(x^3 + kx^2\)M1
Obtain quotient \(x^3 + x^2 + 3x + 2\)A1 There being no remainder
Equate quotient to zero and rearrange to make the subject \(a\)M1
Obtain the given equationA1
Total: 4
Question 6(iii):
AnswerMarks Guidance
AnswerMark Guidance
Use the iterative formula \(a_{n+1} = -\frac{1}{3}(2 + a_n^2 + a_n^3)\) correctly at least onceM1
Obtain final answer \(-0.715\)A1
Show sufficient iterations to 5 d.p. to justify \(-0.715\) to 3 d.p., or show there is a sign change in the interval \((-0.7145, -0.7155)\)A1
Total: 3
## Question 6(i):

| Answer | Mark | Guidance |
|--------|------|----------|
| State $b = 3$ | B1 | |
| **Total: 1** | | |

## Question 6(ii):

| Answer | Mark | Guidance |
|--------|------|----------|
| Commence division by $x - b$ and reach partial quotient $x^3 + kx^2$ | M1 | |
| Obtain quotient $x^3 + x^2 + 3x + 2$ | A1 | There being no remainder |
| Equate quotient to zero and rearrange to make the subject $a$ | M1 | |
| Obtain the given equation | A1 | |
| **Total: 4** | | |

## Question 6(iii):

| Answer | Mark | Guidance |
|--------|------|----------|
| Use the iterative formula $a_{n+1} = -\frac{1}{3}(2 + a_n^2 + a_n^3)$ correctly at least once | M1 | |
| Obtain final answer $-0.715$ | A1 | |
| Show sufficient iterations to 5 d.p. to justify $-0.715$ to 3 d.p., or show there is a sign change in the interval $(-0.7145, -0.7155)$ | A1 | |
| **Total: 3** | | |
6\\
\includegraphics[max width=\textwidth, alt={}, center]{87392b1c-3683-45b4-8d55-36760b5f0cc1-10_547_531_260_806}

The diagram shows the curve $y = x ^ { 4 } - 2 x ^ { 3 } - 7 x - 6$. The curve intersects the $x$-axis at the points $( a , 0 )$ and $( b , 0 )$, where $a < b$. It is given that $b$ is an integer.\\
(i) Find the value of $b$.\\

(ii) Hence show that $a$ satisfies the equation $a = - \frac { 1 } { 3 } \left( 2 + a ^ { 2 } + a ^ { 3 } \right)$.\\

(iii) Use an iterative formula based on the equation in part (ii) to determine $a$ correct to 3 decimal places. Give the result of each iteration to 5 decimal places.\\

\hfill \mbox{\textit{CAIE P3 2019 Q6 [8]}}