OCR MEI FP1 2016 June — Question 1 4 marks

Exam BoardOCR MEI
ModuleFP1 (Further Pure Mathematics 1)
Year2016
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMatrices
TypeArea transformation under matrices
DifficultyModerate -0.3 This is a straightforward application of the area transformation formula (area scales by |det(M)|). Part (i) is routine matrix inversion using the 2×2 formula, and part (ii) requires calculating a determinant and multiplying by the original area from the diagram. Both are standard textbook exercises requiring recall of formulas rather than problem-solving insight.
Spec4.03i Determinant: area scale factor and orientation4.03n Inverse 2x2 matrix

1 The matrix \(\mathbf { M }\) is given by \(\mathbf { M } = \left( \begin{array} { c c } 8 & - 2 \\ p & 1 \end{array} \right)\), where \(p \neq - 4\).
  1. Find the inverse of \(\mathbf { M }\) in terms of \(p\).
  2. \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{578345cb-e7a1-41fd-abf8-a977912965e8-2_1086_885_584_587} \captionsetup{labelformat=empty} \caption{Fig. 1}
    \end{figure} The triangle shown in Fig. 1 undergoes the transformation represented by the matrix \(\left( \begin{array} { c c } 8 & - 2 \\ 3 & 1 \end{array} \right)\). Find the area of the image of the triangle following this transformation.

Question 1:
(i)
AnswerMarks Guidance
\(\det(\mathbf{M}) = 8 + 2p\)M1 Finding determinant
\(\mathbf{M}^{-1} = \frac{1}{8+2p}\begin{pmatrix}1 & 2 \\ -p & 8\end{pmatrix}\)A1 Correct inverse
(ii)
AnswerMarks Guidance
Area of triangle from graph \(= \frac{1}{2}(3)(3) = 4.5\) (reading vertices e.g. \((1,0),(4,-1),(4,5)\))M1
\(\det\mathbf{M} =
Area of image \(= 14 \times 4.5 = 63\)A1
## Question 1:

**(i)**
$\det(\mathbf{M}) = 8 + 2p$ | M1 | Finding determinant
$\mathbf{M}^{-1} = \frac{1}{8+2p}\begin{pmatrix}1 & 2 \\ -p & 8\end{pmatrix}$ | A1 | Correct inverse

**(ii)**
Area of triangle from graph $= \frac{1}{2}(3)(3) = 4.5$ (reading vertices e.g. $(1,0),(4,-1),(4,5)$) | M1 |
$|\det\mathbf{M}| = |8(1)-(-2)(3)| = 14$ | M1 |
Area of image $= 14 \times 4.5 = 63$ | A1 |

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1 The matrix $\mathbf { M }$ is given by $\mathbf { M } = \left( \begin{array} { c c } 8 & - 2 \\ p & 1 \end{array} \right)$, where $p \neq - 4$.\\
(i) Find the inverse of $\mathbf { M }$ in terms of $p$.\\
(ii)

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{578345cb-e7a1-41fd-abf8-a977912965e8-2_1086_885_584_587}
\captionsetup{labelformat=empty}
\caption{Fig. 1}
\end{center}
\end{figure}

The triangle shown in Fig. 1 undergoes the transformation represented by the matrix $\left( \begin{array} { c c } 8 & - 2 \\ 3 & 1 \end{array} \right)$. Find the area of the image of the triangle following this transformation.

\hfill \mbox{\textit{OCR MEI FP1 2016 Q1 [4]}}