OCR MEI FP1 2011 June — Question 8 11 marks

Exam BoardOCR MEI
ModuleFP1 (Further Pure Mathematics 1)
Year2011
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Arithmetic
TypeGiven two complex roots, find all roots
DifficultyStandard +0.3 This is a standard Further Pure 1 question testing the fundamental principle that complex roots of polynomials with real coefficients occur in conjugate pairs. Part (i) requires simple reasoning (4 roots needed, not 3), part (ii) involves routine expansion of factors, and part (iii) is straightforward plotting and finding a circle through four points. While it's Further Maths content, it's a textbook application with no novel insight required, making it slightly easier than average overall.
Spec4.02g Conjugate pairs: real coefficient polynomials4.02j Cubic/quartic equations: conjugate pairs and factor theorem4.02k Argand diagrams: geometric interpretation

8 A polynomial \(\mathrm { P } ( z )\) has real coefficients. Two of the roots of \(\mathrm { P } ( z ) = 0\) are \(2 - \mathrm { j }\) and \(- 1 + 2 \mathrm { j }\).
  1. Explain why \(\mathrm { P } ( z )\) cannot be a cubic. You are given that \(\mathrm { P } ( z )\) is a quartic.
  2. Write down the other roots of \(\mathrm { P } ( z ) = 0\) and hence find \(\mathrm { P } ( z )\) in the form \(z ^ { 4 } + a z ^ { 3 } + b z ^ { 2 } + c z + d\).
  3. Show the roots of \(\mathrm { P } ( z ) = 0\) on an Argand diagram and give, in terms of \(z\), the equation of the circle they lie on.

Question 8(i):
AnswerMarks Guidance
AnswerMark Guidance
Because a cubic can only have a maximum of two complex roots, which must form a conjugate pair.E1
[1]
Question 8(ii):
AnswerMarks Guidance
AnswerMark Guidance
\(2+j,\ -1-2j\)B1, B1
\(P(z) = (z-(2-j))(z-(2+j))(z-(-1+2j))(z-(-1-2j))\)M1 Use of factor theorem
\(= ((z-2)^2+1)((z+1)^2+4)\)M1 Attempt to multiply out factors
\(= (z^2-4z+5)(z^2+2z+5)\)
\(= z^4 - 2z^3 + 2z^2 - 10z + 25\)A4 \(-1\) for each incorrect coefficient
OR using root relationships:
\(\alpha+\beta+\gamma+\delta = 2 \Rightarrow a = -2\)M2 M1 for attempt to use all 4 root relationships; M2 for all correct
\(\alpha\beta+\alpha\gamma+\alpha\delta+\beta\gamma+\beta\delta+\gamma\delta = 2 \Rightarrow b = 2\)B1 \(a = -2\)
\(\alpha\beta\gamma+\alpha\beta\delta+\alpha\gamma\delta+\beta\gamma\delta = 10 \Rightarrow c = -10\)A3 \(b, c, d\) correct \(-1\) for each incorrect
\(\alpha\beta\gamma\delta = 25 \Rightarrow d = 25\) \(-1\) for \(P(z)\) not explicit, following A4 or B1A3
\(\Rightarrow P(z) = z^4 - 2z^3 + 2z^2 - 10z + 25\)
[8]
Question 8(iii):
AnswerMarks Guidance
AnswerMark Guidance
Argand diagram with all four roots correctly plotted and labelledB1 All correct with annotation on axes or labels
\(z = \sqrt{5}\)
[2]
# Question 8(i):

| Answer | Mark | Guidance |
|--------|------|----------|
| Because a cubic can only have a maximum of two complex roots, which must form a conjugate pair. | E1 | |
| | **[1]** | |

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# Question 8(ii):

| Answer | Mark | Guidance |
|--------|------|----------|
| $2+j,\ -1-2j$ | B1, B1 | |
| $P(z) = (z-(2-j))(z-(2+j))(z-(-1+2j))(z-(-1-2j))$ | M1 | Use of factor theorem |
| $= ((z-2)^2+1)((z+1)^2+4)$ | M1 | Attempt to multiply out factors |
| $= (z^2-4z+5)(z^2+2z+5)$ | | |
| $= z^4 - 2z^3 + 2z^2 - 10z + 25$ | A4 | $-1$ for each incorrect coefficient |
| **OR** using root relationships: | | |
| $\alpha+\beta+\gamma+\delta = 2 \Rightarrow a = -2$ | M2 | M1 for attempt to use all 4 root relationships; M2 for all correct |
| $\alpha\beta+\alpha\gamma+\alpha\delta+\beta\gamma+\beta\delta+\gamma\delta = 2 \Rightarrow b = 2$ | B1 | $a = -2$ |
| $\alpha\beta\gamma+\alpha\beta\delta+\alpha\gamma\delta+\beta\gamma\delta = 10 \Rightarrow c = -10$ | A3 | $b, c, d$ correct $-1$ for each incorrect |
| $\alpha\beta\gamma\delta = 25 \Rightarrow d = 25$ | | $-1$ for $P(z)$ not explicit, following A4 or B1A3 |
| $\Rightarrow P(z) = z^4 - 2z^3 + 2z^2 - 10z + 25$ | | |
| | **[8]** | |

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# Question 8(iii):

| Answer | Mark | Guidance |
|--------|------|----------|
| Argand diagram with all four roots correctly plotted and labelled | B1 | All correct with annotation on axes or labels |
| $|z| = \sqrt{5}$ | B1 | |
| | **[2]** | |

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8 A polynomial $\mathrm { P } ( z )$ has real coefficients. Two of the roots of $\mathrm { P } ( z ) = 0$ are $2 - \mathrm { j }$ and $- 1 + 2 \mathrm { j }$.\\
(i) Explain why $\mathrm { P } ( z )$ cannot be a cubic.

You are given that $\mathrm { P } ( z )$ is a quartic.\\
(ii) Write down the other roots of $\mathrm { P } ( z ) = 0$ and hence find $\mathrm { P } ( z )$ in the form $z ^ { 4 } + a z ^ { 3 } + b z ^ { 2 } + c z + d$.\\
(iii) Show the roots of $\mathrm { P } ( z ) = 0$ on an Argand diagram and give, in terms of $z$, the equation of the circle they lie on.

\hfill \mbox{\textit{OCR MEI FP1 2011 Q8 [11]}}