OCR S4 2009 June — Question 6 13 marks

Exam BoardOCR
ModuleS4 (Statistics 4)
Year2009
SessionJune
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoment generating functions
TypeShow unbiased estimator
DifficultyChallenging +1.8 This is a Further Maths Statistics question requiring understanding of MGFs, unbiased estimators, and efficiency. Part (i) is routine integration, but parts (ii)-(iv) require careful algebraic manipulation of expectations and variance calculations for linear combinations of random variables. The efficiency comparison demands computing and comparing variances of two complex estimators, which is non-trivial but follows standard S4 techniques without requiring novel insight.
Spec5.05b Unbiased estimates: of population mean and variance

6 The continuous random variable \(X\) has probability density function given by $$\mathrm { f } ( x ) = \begin{cases} 0 & x < a , \\ \mathrm { e } ^ { - ( x - a ) } & x \geqslant a , \end{cases}$$ where \(a\) is a constant. \(X _ { 1 } , X _ { 2 } , \ldots , X _ { n }\) are \(n\) independent observations of \(X\), where \(n \geqslant 4\).
  1. Show that \(\mathrm { E } ( X ) = a + 1\). \(T _ { 1 }\) and \(T _ { 2 }\) are proposed estimators of \(a\), where $$T _ { 1 } = X _ { 1 } + 2 X _ { 2 } - X _ { 3 } - X _ { 4 } - 1 \quad \text { and } \quad T _ { 2 } = \frac { X _ { 1 } + X _ { 2 } } { 4 } + \frac { X _ { 3 } + X _ { 4 } + \ldots + X _ { n } } { 2 ( n - 2 ) } - 1 .$$
  2. Show that \(T _ { 1 }\) and \(T _ { 2 }\) are unbiased estimators of \(a\).
  3. Determine which is the more efficient estimator.
  4. Suggest another unbiased estimator of \(a\) using all of the \(n\) observations.

(i)
AnswerMarks Guidance
Obtain derivative \(k(37 + 10y - 2y^2)^{-\frac{1}{2}}f(y)\)M1 any constant \(k\); any linear function for \(f\)
Obtain \(\frac{1}{4}(10 - 4y)(37 + 10y - 2y^2)^{-\frac{1}{2}}\)A1 2 or equiv
(ii)
AnswerMarks Guidance
Either: Sub'te \(y = 3\) in expression for \(\frac{dx}{dy}\)*M1
Take reciprocal of expression/value*M1 and without change of sign
Obtain \(-7\) for gradient of tangentA1
Attempt equation of tangentM1 dep *M *M
Obtain \(y = -7x + 52\)A1 5 and no second equation
Or: Sub'te \(y = 3\) in expression for \(\frac{dx}{dy}\)M1
Attempt formation of eq'n \(x = m'y + c\)M1 where \(m'\) is attempt at \(\frac{dy}{dx}\)
Obtain \(x = -7 - \frac{1}{2}(y - 3)\)A1 or equiv
Attempt rearrangement to
### (i)
Obtain derivative $k(37 + 10y - 2y^2)^{-\frac{1}{2}}f(y)$ | M1 | any constant $k$; any linear function for $f$ |
Obtain $\frac{1}{4}(10 - 4y)(37 + 10y - 2y^2)^{-\frac{1}{2}}$ | A1 2 | or equiv |

### (ii)
Either: Sub'te $y = 3$ in expression for $\frac{dx}{dy}$ | *M1 | |
Take reciprocal of expression/value | *M1 | and without change of sign |
Obtain $-7$ for gradient of tangent | A1 |
Attempt equation of tangent | M1 | dep *M *M |
Obtain $y = -7x + 52$ | A1 5 | and no second equation |

Or: Sub'te $y = 3$ in expression for $\frac{dx}{dy}$ | M1 |
Attempt formation of eq'n $x = m'y + c$ | M1 | where $m'$ is attempt at $\frac{dy}{dx}$ |
Obtain $x = -7 - \frac{1}{2}(y - 3)$ | A1 | or equiv |
Attempt rearrangement to
6 The continuous random variable $X$ has probability density function given by

$$\mathrm { f } ( x ) = \begin{cases} 0 & x < a , \\ \mathrm { e } ^ { - ( x - a ) } & x \geqslant a , \end{cases}$$

where $a$ is a constant. $X _ { 1 } , X _ { 2 } , \ldots , X _ { n }$ are $n$ independent observations of $X$, where $n \geqslant 4$.\\
(i) Show that $\mathrm { E } ( X ) = a + 1$.\\
$T _ { 1 }$ and $T _ { 2 }$ are proposed estimators of $a$, where

$$T _ { 1 } = X _ { 1 } + 2 X _ { 2 } - X _ { 3 } - X _ { 4 } - 1 \quad \text { and } \quad T _ { 2 } = \frac { X _ { 1 } + X _ { 2 } } { 4 } + \frac { X _ { 3 } + X _ { 4 } + \ldots + X _ { n } } { 2 ( n - 2 ) } - 1 .$$

(ii) Show that $T _ { 1 }$ and $T _ { 2 }$ are unbiased estimators of $a$.\\
(iii) Determine which is the more efficient estimator.\\
(iv) Suggest another unbiased estimator of $a$ using all of the $n$ observations.

\hfill \mbox{\textit{OCR S4 2009 Q6 [13]}}