OCR S1 2015 June — Question 3 6 marks

Exam BoardOCR
ModuleS1 (Statistics 1)
Year2015
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHypothesis test of Spearman’s rank correlation coefficien
TypeCalculate and interpret coefficient
DifficultyModerate -0.8 This is a straightforward application of Spearman's rank correlation formula with data already provided in rank order. The calculation is mechanical (computing d² values and applying the formula), and the interpretation requires only basic understanding that negative r_s indicates inverse relationship. No problem-solving insight needed, just routine procedure execution.
Spec5.08e Spearman rank correlation

3 An expert tested the quality of the wines produced by a vineyard in 9 particular years. He placed them in the following order, starting with the best. $$\begin{array} { l l l l l l l l l } 1980 & 1983 & 1981 & 1982 & 1984 & 1985 & 1987 & 1986 & 1988 \end{array}$$
  1. Calculate Spearman's rank correlation coefficient, \(r _ { s }\), between the year of production and the quality of these wines. The years should be ranked from the earliest (1) to the latest (9).
  2. State what this value of \(r _ { s }\) shows in this context.

Question 3:
Part (i)
Year: 80 81 82 83 84 85 86 87 88
Age: 1 2 3 4 5 6 7 8 9
AnswerMarks Guidance
Quality: 1 3 4 2 5 6 8 7 9M1 Attempt ranks; Y 80 83 81 82 84 85 87 86 88; Q1 2 3 4 5 6 7 8 9; A 1 4 2 3 5 6 8 7 9
A1Correct ranks; Allow both sets of ranks reversed
Attempt \(\Sigma d^2\) \((= 8)\)M1
\(1 - \frac{6 \times 8}{9 \times (81-1)}\)M1
\(= \frac{14}{15}\) or \(0.9\dot{3}\) or \(0.933\) (3 sf)A1 NB \(0.9\dot{3}\) is correct; One set reversed max 4 marks giving \(-\frac{14}{15}\) or \(-0.9\dot{3}\) or \(-0.933\)
[5]
Part (ii)
AnswerMarks Guidance
Older is better or newer is worse; As age increases, quality increases; Must imply older is better, ie "good (or positive) corr'n between age and quality" is not enoughB1 No ft from (i); \(-0.933\) in (i) leads to same conclusion as \(+0.933\) in (ii); Nothing contradictory seen; NOT as year increases quality increases; NOT High/strong/good corr'n/agreement/rel'nship between age and quality
[1]
# Question 3:

## Part (i)
Year: 80 81 82 83 84 85 86 87 88

Age: 1 2 3 4 5 6 7 8 9

Quality: 1 3 4 2 5 6 8 7 9 | M1 | Attempt ranks; Y 80 83 81 82 84 85 87 86 88; Q1 2 3 4 5 6 7 8 9; A 1 4 2 3 5 6 8 7 9

| A1 | Correct ranks; Allow both sets of ranks reversed

Attempt $\Sigma d^2$ $(= 8)$ | M1 |

$1 - \frac{6 \times 8}{9 \times (81-1)}$ | M1 |

$= \frac{14}{15}$ or $0.9\dot{3}$ or $0.933$ (3 sf) | A1 | NB $0.9\dot{3}$ is correct; One set reversed max 4 marks giving $-\frac{14}{15}$ or $-0.9\dot{3}$ or $-0.933$

**[5]**

## Part (ii)
Older is better or newer is worse; As age increases, quality increases; Must imply older is better, ie "good (or positive) corr'n between age and quality" is not enough | B1 | No ft from (i); $-0.933$ in (i) leads to same conclusion as $+0.933$ in (ii); Nothing contradictory seen; NOT as year increases quality increases; NOT High/strong/good corr'n/agreement/rel'nship between age and quality

**[1]**

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3 An expert tested the quality of the wines produced by a vineyard in 9 particular years. He placed them in the following order, starting with the best.

$$\begin{array} { l l l l l l l l l } 
1980 & 1983 & 1981 & 1982 & 1984 & 1985 & 1987 & 1986 & 1988
\end{array}$$

(i) Calculate Spearman's rank correlation coefficient, $r _ { s }$, between the year of production and the quality of these wines. The years should be ranked from the earliest (1) to the latest (9).\\
(ii) State what this value of $r _ { s }$ shows in this context.

\hfill \mbox{\textit{OCR S1 2015 Q3 [6]}}