OCR S1 2015 June — Question 2 10 marks

Exam BoardOCR
ModuleS1 (Statistics 1)
Year2015
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicData representation
TypeEstimate single values from cumulative frequency graph
DifficultyEasy -1.3 This is a straightforward cumulative frequency graph reading exercise requiring only basic graph interpretation skills (reading values, finding differences, calculating percentages) and standard box plot construction. All parts are routine S1 techniques with no problem-solving or conceptual challenges beyond direct application of learned procedures.
Spec2.02a Interpret single variable data: tables and diagrams2.02h Recognize outliers

2 The masses, in grams, of 400 plums were recorded. The masses were then collected into class intervals of width 5 g and a cumulative frequency graph was drawn, as shown below. \includegraphics[max width=\textwidth, alt={}, center]{e5957185-5fe3-45d9-9ab3-c2aab9cbd8dd-3_1045_1401_358_333}
  1. Find the number of plums with masses in the interval 40 g to 45 g .
  2. Find the percentage of plums with masses greater than 70 g .
  3. Give estimates of the highest and lowest masses in the sample, explaining why their exact values cannot be read from the graph.
  4. On the graph paper in the answer book, draw a box-and-whisker plot to illustrate the masses of the plums in the sample.
  5. Comment briefly on the shape of the distribution of masses.

Question 2:
Part (i)
AnswerMarks Guidance
35B1 Allow 30 to 40 inclusive
[1]
Part (ii)
AnswerMarks Guidance
\(\frac{50 \pm 2}{400} \times 100\)M1 NOT \(\frac{50\pm2}{450} \times 100\); NOT \(\frac{100\pm2}{400\text{ or }450} \times 100\)
\(= 12\%\) to \(13\%\)A1 NOT \(\frac{350\pm2}{400} \times 100\) (unless sub from 100)
[2]
Part (iii)
AnswerMarks Guidance
e.g. 7.5, 87.5 or 5, 90 or 5–10, 85–90B1 or any values in intervals 5–10 & 85–90; NOT "Because it's cumulative frequency"
"Classes" or "intervals" or "groups" or "mid-points" or "bounds" seen; Data lostB1 No raw data given. Not have each data value; Exact values not given or can't be read off; NOT "Because it's a line of best fit"; NOT "Because graph is difficult to read"; NOT "because graph is a curve"; NOT "Cont data has no exact data pts"
[2]
Question 2 (continued):
Part (iv)
AnswerMarks Guidance
Median \(= 39 \pm 1\) drawnB1 or stated; Mark diagram even if contradicts statements
Quartiles \(= 25 \pm 1,\ 55 \pm 1\) drawnB1 or stated; statements of values in (iv) or (iii)
Ends in ranges 5–10 & 85–90 drawnB1f or ft (iii); If no diagram, award max B1B1B1 for statements of med, quartiles & ends
Correct B&W plot \(\pm 1\) drawnB1f or ft (iii) mark intention (allow unruled lines)
[4]
Part (v)
AnswerMarks Guidance
Stretched out at top endB1 Positive skew; Skewed to right (or to higher values); Larger skewness at top; Larger plums more spread than smaller ones; NOT any of below: more large extremes than small extremes; IQR is towards the lower end; skewed to the left; majority below 39; distribution towards lower end
Not symmetrical; More concentrated towards lower end; More values (or data) in lower half of range; Median closer to lowest value; Average towards lower end; More plums have lower masses; Majority of distribution towards lower end; More below 50 (or 45); Upper whisker longer than lower whisker Ignore all else; No need for context
[1]
# Question 2:

## Part (i)
35 | B1 | Allow 30 to 40 inclusive

**[1]**

## Part (ii)
$\frac{50 \pm 2}{400} \times 100$ | M1 | NOT $\frac{50\pm2}{450} \times 100$; NOT $\frac{100\pm2}{400\text{ or }450} \times 100$

$= 12\%$ to $13\%$ | A1 | NOT $\frac{350\pm2}{400} \times 100$ (unless sub from 100)

**[2]**

## Part (iii)
e.g. 7.5, 87.5 or 5, 90 or 5–10, 85–90 | B1 | or any values in intervals 5–10 & 85–90; NOT "Because it's cumulative frequency"

"Classes" or "intervals" or "groups" or "mid-points" or "bounds" seen; Data lost | B1 | No raw data given. Not have each data value; Exact values not given or can't be read off; NOT "Because it's a line of best fit"; NOT "Because graph is difficult to read"; NOT "because graph is a curve"; NOT "Cont data has no exact data pts"

**[2]**

---

# Question 2 (continued):

## Part (iv)
Median $= 39 \pm 1$ drawn | B1 | or stated; Mark diagram even if contradicts statements

Quartiles $= 25 \pm 1,\ 55 \pm 1$ drawn | B1 | or stated; statements of values in (iv) or (iii)

Ends in ranges 5–10 & 85–90 drawn | B1f | or ft (iii); If no diagram, award max B1B1B1 for statements of med, quartiles & ends

Correct B&W plot $\pm 1$ drawn | B1f | or ft (iii) mark intention (allow unruled lines)

**[4]**

## Part (v)
Stretched out at top end | B1 | Positive skew; Skewed to right (or to higher values); Larger skewness at top; Larger plums more spread than smaller ones; NOT any of below: more large extremes than small extremes; IQR is towards the lower end; skewed to the left; majority below 39; distribution towards lower end

Not symmetrical; More concentrated towards lower end; More values (or data) in lower half of range; Median closer to lowest value; Average towards lower end; More plums have lower masses; Majority of distribution towards lower end; More below 50 (or 45); Upper whisker longer than lower whisker | | Ignore all else; No need for context

**[1]**

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2 The masses, in grams, of 400 plums were recorded. The masses were then collected into class intervals of width 5 g and a cumulative frequency graph was drawn, as shown below.\\
\includegraphics[max width=\textwidth, alt={}, center]{e5957185-5fe3-45d9-9ab3-c2aab9cbd8dd-3_1045_1401_358_333}\\
(i) Find the number of plums with masses in the interval 40 g to 45 g .\\
(ii) Find the percentage of plums with masses greater than 70 g .\\
(iii) Give estimates of the highest and lowest masses in the sample, explaining why their exact values cannot be read from the graph.\\
(iv) On the graph paper in the answer book, draw a box-and-whisker plot to illustrate the masses of the plums in the sample.\\
(v) Comment briefly on the shape of the distribution of masses.

\hfill \mbox{\textit{OCR S1 2015 Q2 [10]}}