CAIE P3 2015 June — Question 6 9 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2015
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeDerive equation from integral condition
DifficultyStandard +0.3 This is a straightforward multi-part question requiring integration by parts (standard technique), algebraic rearrangement, and mechanical application of an iterative formula. All steps are routine for P3 level with no novel insight required, making it slightly easier than average.
Spec1.08i Integration by parts1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

6 It is given that \(\int _ { 0 } ^ { a } x \cos x \mathrm {~d} x = 0.5\), where \(0 < a < \frac { 1 } { 2 } \pi\).
  1. Show that \(a\) satisfies the equation \(\sin a = \frac { 1.5 - \cos a } { a }\).
  2. Verify by calculation that \(a\) is greater than 1 .
  3. Use the iterative formula $$a _ { n + 1 } = \sin ^ { - 1 } \left( \frac { 1.5 - \cos a _ { n } } { a _ { n } } \right)$$ to determine the value of \(a\) correct to 4 decimal places, giving the result of each iteration to 6 decimal places.

AnswerMarks Guidance
(i) Integrate and reach \(\pm x\sin x \mp \int \sin x \, dx\)M1*
Obtain integral \(x\sin x + \cos x\)A1
Substitute limits correctly, must be seen since AG, and equate result to 0.5M1(dep*)
Obtain the given form of the equationA1 4
(ii) EITHER: Consider the sign of a relevant expression at \(a = 1\) and at another relevant value, e.g. \(a = 1.5 \leq \frac{\pi}{2}\)M1
OR: Using limits correctly, consider the sign of \([x\sin x + \cos x]_0^a - 0.5\), or compare the value of \([x\sin x + \cos x]_0^a\) with 0.5, for \(a = 1\) AND for another relevant value, e.g. \(a = 1.5 \leq \frac{\pi}{2}\)M1
Complete the argument, so change of sign, or above and below stated, both with correct calculated valuesA1 2
(iii) Use the iterative formula correctly at least onceM1
Obtain final answer 1.2461A1
Show sufficient iterations to 6 d.p. to justify 1.2461 to 4 d.p., or show there is a sign change in the interval (1.24605, 1.24615)A1 3
**(i)** Integrate and reach $\pm x\sin x \mp \int \sin x \, dx$ | M1* |

Obtain integral $x\sin x + \cos x$ | A1 |

Substitute limits correctly, must be seen since AG, and equate result to 0.5 | M1(dep*) |

Obtain the given form of the equation | A1 | 4 |

**(ii)** **EITHER:** Consider the sign of a relevant expression at $a = 1$ and at another relevant value, e.g. $a = 1.5 \leq \frac{\pi}{2}$ | M1 |

**OR:** Using limits correctly, consider the sign of $[x\sin x + \cos x]_0^a - 0.5$, or compare the value of $[x\sin x + \cos x]_0^a$ with 0.5, for $a = 1$ AND for another relevant value, e.g. $a = 1.5 \leq \frac{\pi}{2}$ | M1 |

Complete the argument, so change of sign, or above and below stated, both with correct calculated values | A1 | 2 |

**(iii)** Use the iterative formula correctly at least once | M1 |

Obtain final answer 1.2461 | A1 |

Show sufficient iterations to 6 d.p. to justify 1.2461 to 4 d.p., or show there is a sign change in the interval (1.24605, 1.24615) | A1 | 3 |
6 It is given that $\int _ { 0 } ^ { a } x \cos x \mathrm {~d} x = 0.5$, where $0 < a < \frac { 1 } { 2 } \pi$.\\
(i) Show that $a$ satisfies the equation $\sin a = \frac { 1.5 - \cos a } { a }$.\\
(ii) Verify by calculation that $a$ is greater than 1 .\\
(iii) Use the iterative formula

$$a _ { n + 1 } = \sin ^ { - 1 } \left( \frac { 1.5 - \cos a _ { n } } { a _ { n } } \right)$$

to determine the value of $a$ correct to 4 decimal places, giving the result of each iteration to 6 decimal places.

\hfill \mbox{\textit{CAIE P3 2015 Q6 [9]}}