CAIE P3 2015 June — Question 4 6 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2015
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProduct & Quotient Rules
TypeFind stationary points coordinates
DifficultyStandard +0.3 This is a straightforward application of the quotient rule to find dy/dx, setting it equal to zero, and solving for x. The algebra involves exponentials but is routine for P3 level. Finding the y-coordinate requires simple substitution. Slightly above average difficulty due to the exponential manipulation required, but still a standard textbook exercise with no novel insight needed.
Spec1.07n Stationary points: find maxima, minima using derivatives1.07r Chain rule: dy/dx = dy/du * du/dx and connected rates

4 The curve with equation \(y = \frac { \mathrm { e } ^ { 2 x } } { 4 + \mathrm { e } ^ { 3 x } }\) has one stationary point. Find the exact values of the coordinates of this point.

AnswerMarks Guidance
Use correct quotient or product ruleM1
Obtain correct derivative in any formA1
Equate derivative to zero and obtain a horizontal equationM1
Carry out complete method for solving an equation of the form \(ae^{3x} = b\), or \(ae^{5x} = be^{2x}\)M1
Obtain \(x = \ln 2\), or exact equivalentA1
Obtain \(y = \frac{1}{3}\), or exact equivalentA1 6
Use correct quotient or product rule | M1 |

Obtain correct derivative in any form | A1 |

Equate derivative to zero and obtain a horizontal equation | M1 |

Carry out complete method for solving an equation of the form $ae^{3x} = b$, or $ae^{5x} = be^{2x}$ | M1 |

Obtain $x = \ln 2$, or exact equivalent | A1 |

Obtain $y = \frac{1}{3}$, or exact equivalent | A1 | 6 |
4 The curve with equation $y = \frac { \mathrm { e } ^ { 2 x } } { 4 + \mathrm { e } ^ { 3 x } }$ has one stationary point. Find the exact values of the coordinates of this point.

\hfill \mbox{\textit{CAIE P3 2015 Q4 [6]}}