OCR MEI C4 2013 January — Question 4 8 marks

Exam BoardOCR MEI
ModuleC4 (Core Mathematics 4)
Year2013
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVolumes of Revolution
TypeVolume with numerical methods
DifficultyStandard +0.3 Part (a) is a standard volume of revolution requiring the formula V = π∫y² dx, which simplifies nicely since y² = 1 + e^(2x) integrates directly to x + ½e^(2x). Part (b) involves routine trapezium rule application and conceptual understanding of numerical methods convergence. This is slightly easier than average as the integration in (a) is straightforward and part (b) tests standard numerical methods without requiring novel problem-solving.
Spec1.06a Exponential function: a^x and e^x graphs and properties1.09f Trapezium rule: numerical integration4.08d Volumes of revolution: about x and y axes

4 Fig. 4 shows the curve \(y = \sqrt { 1 + \mathrm { e } ^ { 2 x } }\), and the region between the curve, the \(x\)-axis, the \(y\)-axis and the line \(x = 2\). \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{9bceee25-35bd-448b-a4a2-1a5667be5f11-02_650_727_1176_653} \captionsetup{labelformat=empty} \caption{Fig. 4}
\end{figure}
  1. Find the exact volume of revolution when the shaded region is rotated through \(360 ^ { \circ }\) about the \(x\)-axis.
    1. Complete the table of values, and use the trapezium rule with 4 strips to estimate the area of the shaded region.
      \(x\)00.511.52
      \(y\)1.92832.89644.5919
    2. The trapezium rule for \(\int _ { 0 } ^ { 2 } \sqrt { 1 + \mathrm { e } ^ { 2 x } } \mathrm {~d} x\) with 8 and 16 strips gives 6.797 and 6.823, although not necessarily in that order. Without doing the calculations, say which result is which, explaining your reasoning.

Question 4:
AnswerMarks Guidance
AnswerMark Guidance
\(n(4,4) = \binom{8}{4} = 70\)M1 For method using combinations
\(= 70\)A1 [2]
# Question 4:

| Answer | Mark | Guidance |
|--------|------|----------|
| $n(4,4) = \binom{8}{4} = 70$ | M1 | For method using combinations |
| $= 70$ | A1 | [2] |

---
4 Fig. 4 shows the curve $y = \sqrt { 1 + \mathrm { e } ^ { 2 x } }$, and the region between the curve, the $x$-axis, the $y$-axis and the line $x = 2$.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{9bceee25-35bd-448b-a4a2-1a5667be5f11-02_650_727_1176_653}
\captionsetup{labelformat=empty}
\caption{Fig. 4}
\end{center}
\end{figure}
\begin{enumerate}[label=(\alph*)]
\item Find the exact volume of revolution when the shaded region is rotated through $360 ^ { \circ }$ about the $x$-axis.
\item \begin{enumerate}[label=(\roman*)]
\item Complete the table of values, and use the trapezium rule with 4 strips to estimate the area of the shaded region.

\begin{center}
\begin{tabular}{ | l | l | l | l | l | l | }
\hline
$x$ & 0 & 0.5 & 1 & 1.5 & 2 \\
\hline
$y$ &  & 1.9283 & 2.8964 & 4.5919 &  \\
\hline
\end{tabular}
\end{center}
\item The trapezium rule for $\int _ { 0 } ^ { 2 } \sqrt { 1 + \mathrm { e } ^ { 2 x } } \mathrm {~d} x$ with 8 and 16 strips gives 6.797 and 6.823, although not necessarily in that order. Without doing the calculations, say which result is which, explaining your reasoning.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{OCR MEI C4 2013 Q4 [8]}}