| Exam Board | OCR MEI |
|---|---|
| Module | C3 (Core Mathematics 3) |
| Year | 2009 |
| Session | January |
| Marks | 3 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Modulus function |
| Type | Solve |linear| < constant (pure inequality) |
| Difficulty | Easy -1.8 This is a straightforward application of the basic definition of modulus inequalities, requiring only the standard technique of rewriting |x - 1| < 3 as -3 < x - 1 < 3, then adding 1 throughout to get -2 < x < 4. It's a single-step routine exercise testing recall of a fundamental concept with no problem-solving required. |
| Spec | 1.02l Modulus function: notation, relations, equations and inequalities |
1 Solve the inequality $| x - 1 | < 3$.
\hfill \mbox{\textit{OCR MEI C3 2009 Q1 [3]}}