CAIE P3 2013 June — Question 9 10 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2013
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferentiating Transcendental Functions
TypeFind stationary points - trigonometric functions
DifficultyChallenging +1.2 Part (i) requires product rule and chain rule to differentiate sin²(2x)cos(x), then solving the resulting trigonometric equation for stationary points—moderately challenging but standard A-level technique. Part (ii) involves a guided substitution to convert the integral, requiring double angle formula manipulation and polynomial integration—straightforward once the substitution is applied. The combination of differentiation and integration with trigonometric identities places this slightly above average difficulty.
Spec1.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.07n Stationary points: find maxima, minima using derivatives1.08h Integration by substitution

9 \includegraphics[max width=\textwidth, alt={}, center]{436d891d-92ee-4076-8369-db756d413979-3_307_601_1553_772} The diagram shows the curve \(y = \sin ^ { 2 } 2 x \cos x\) for \(0 \leqslant x \leqslant \frac { 1 } { 2 } \pi\), and its maximum point \(M\).
  1. Find the \(x\)-coordinate of \(M\).
  2. Using the substitution \(u = \sin x\), find by integration the area of the shaded region bounded by the curve and the \(x\)-axis.

AnswerMarks Guidance
(i) Use product ruleM1
Obtain correct derivative in any form, e.g. \(4\sin 2x \cos 2x \cos x - \sin^2 2x \sin x\)A1
Equate derivative to zero and use a double angle formulaM1*
Reduce equation to one in a single trig functionM1 (dep*)
Obtain a correct equation in any form, e.g. \(10 \cos^3 x = 6 \cos x\), \(4 = 10 \sin^2 x\) or \(4 = 10 \sin^2 x\)A1
Solve and obtain \(x = 0.685\)A1 [6 marks]
(ii) Using \(du = \pm \cos x \, dx\), or equivalent, express integral in terms of \(u\) and \(du\)M1
Obtain \([4u^2(1 - u^2)] \, du\), or equivalentA1
Use limits \(u = 0\) and \(u = 1\) in an integral of the form \(au^3 + bu^5\)M1
Obtain answer \(\frac{8}{15}\) (or \(0.533\))A1 [4 marks total]
**(i)** Use product rule | M1 |
Obtain correct derivative in any form, e.g. $4\sin 2x \cos 2x \cos x - \sin^2 2x \sin x$ | A1 |
Equate derivative to zero and use a double angle formula | M1* |
Reduce equation to one in a single trig function | M1 (dep*) |
Obtain a correct equation in any form, e.g. $10 \cos^3 x = 6 \cos x$, $4 = 10 \sin^2 x$ or $4 = 10 \sin^2 x$ | A1 |
Solve and obtain $x = 0.685$ | A1 | [6 marks]

**(ii)** Using $du = \pm \cos x \, dx$, or equivalent, express integral in terms of $u$ and $du$ | M1 |
Obtain $[4u^2(1 - u^2)] \, du$, or equivalent | A1 |
Use limits $u = 0$ and $u = 1$ in an integral of the form $au^3 + bu^5$ | M1 |
Obtain answer $\frac{8}{15}$ (or $0.533$) | A1 | [4 marks total]

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9\\
\includegraphics[max width=\textwidth, alt={}, center]{436d891d-92ee-4076-8369-db756d413979-3_307_601_1553_772}

The diagram shows the curve $y = \sin ^ { 2 } 2 x \cos x$ for $0 \leqslant x \leqslant \frac { 1 } { 2 } \pi$, and its maximum point $M$.\\
(i) Find the $x$-coordinate of $M$.\\
(ii) Using the substitution $u = \sin x$, find by integration the area of the shaded region bounded by the curve and the $x$-axis.

\hfill \mbox{\textit{CAIE P3 2013 Q9 [10]}}