| Exam Board | OCR |
|---|
| Module | C2 (Core Mathematics 2) |
|---|
| Year | 2014 |
|---|
| Session | June |
|---|
| Topic | Trig Equations |
|---|
4
- Show that the equation
$$\sin x - \cos x = \frac { 6 \cos x } { \tan x }$$
can be expressed in the form
$$\tan ^ { 2 } x - \tan x - 6 = 0 .$$
- Hence solve the equation \(\sin x - \cos x = \frac { 6 \cos x } { \tan x }\) for \(0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }\).