OCR C2 2014 June — Question 1 6 marks

Exam BoardOCR
ModuleC2 (Core Mathematics 2)
Year2014
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSine and Cosine Rules
TypePoint on side of triangle
DifficultyStandard +0.3 This is a straightforward multi-part question testing standard sine/cosine rule applications. Part (i) uses the basic area formula (1/2)ab sin C, part (ii) applies the cosine rule directly, and part (iii) uses the sine rule. All steps are routine with no problem-solving insight required, making it slightly easier than average but not trivial due to the multi-step nature.
Spec1.05b Sine and cosine rules: including ambiguous case1.05c Area of triangle: using 1/2 ab sin(C)

1 \includegraphics[max width=\textwidth, alt={}, center]{9e95415c-00f5-4b52-a443-0b946602b3b4-2_426_1244_280_413} The diagram shows triangle \(A B C\), with \(A B = 8 \mathrm {~cm}\), angle \(B A C = 65 ^ { \circ }\) and angle \(B C A = 30 ^ { \circ }\). The point \(D\) is on \(A C\) such that \(A D = 10 \mathrm {~cm}\).
  1. Find the area of triangle \(A B D\).
  2. Find the length of \(B D\).
  3. Find the length of \(B C\).

Question 1:
Part (i)
AnswerMarks Guidance
AnswerMark Guidance
\(\text{area} = \frac{1}{2} \times 8 \times 10 \times \sin 65°\)M1 Attempt area of triangle using \(\frac{1}{2}ab\sin\theta\). Must be correct formula including \(\frac{1}{2}\). Allow if evaluated in radian mode (gives 33.1). If using \(\frac{1}{2} \times b \times h\), then must be valid use of trig to find \(h\)
\(= 36.3\)A1 Obtain 36.3 or better. If \(> 3\)sf, allow answer rounding to 36.25 with no errors seen
Part (ii)
AnswerMarks Guidance
AnswerMark Guidance
\(BD^2 = 8^2 + 10^2 - 2 \times 8 \times 10 \times \cos 65°\)M1 Attempt use of correct cosine rule. Allow M1 if not square rooted, as long as \(BD^2\) seen. Allow if evaluated in radian mode (gives 15.9). Allow if correct formula seen but then evaluated incorrectly. Allow any equiv method with valid use of trig
\(BD = 9.82\)A1 Obtain 9.82 or better. If \(> 3\)sf, allow answer rounding to 9.817 with no errors seen
Part (iii)
AnswerMarks Guidance
AnswerMark Guidance
\(\frac{BC}{\sin 65} = \frac{8}{\sin 30}\)M1 Attempt use of correct sine rule (or equiv). Must get as far as attempting \(BC\), not just quoting correct sine rule. Allow any equiv method with valid use of trig including attempt at any angles used. If using their \(BD\) from part (ii) it must have been a valid attempt
\(BC = 14.5\)A1 Obtain 14.5 or better. If \(> 3\)sf, allow answer rounding to 14.5 with no errors in method seen. In multi-step solutions (e.g. using 9.82) interim values may be slightly inaccurate — allow A1 if answer rounds to 14.5
# Question 1:

## Part (i)
| Answer | Mark | Guidance |
|--------|------|----------|
| $\text{area} = \frac{1}{2} \times 8 \times 10 \times \sin 65°$ | M1 | Attempt area of triangle using $\frac{1}{2}ab\sin\theta$. Must be correct formula including $\frac{1}{2}$. Allow if evaluated in radian mode (gives 33.1). If using $\frac{1}{2} \times b \times h$, then must be valid use of trig to find $h$ |
| $= 36.3$ | A1 | Obtain 36.3 or better. If $> 3$sf, allow answer rounding to 36.25 with no errors seen |

## Part (ii)
| Answer | Mark | Guidance |
|--------|------|----------|
| $BD^2 = 8^2 + 10^2 - 2 \times 8 \times 10 \times \cos 65°$ | M1 | Attempt use of correct cosine rule. Allow M1 if not square rooted, as long as $BD^2$ seen. Allow if evaluated in radian mode (gives 15.9). Allow if correct formula seen but then evaluated incorrectly. Allow any equiv method with valid use of trig |
| $BD = 9.82$ | A1 | Obtain 9.82 or better. If $> 3$sf, allow answer rounding to 9.817 with no errors seen |

## Part (iii)
| Answer | Mark | Guidance |
|--------|------|----------|
| $\frac{BC}{\sin 65} = \frac{8}{\sin 30}$ | M1 | Attempt use of correct sine rule (or equiv). Must get as far as attempting $BC$, not just quoting correct sine rule. Allow any equiv method with valid use of trig including attempt at any angles used. If using their $BD$ from part (ii) it must have been a valid attempt |
| $BC = 14.5$ | A1 | Obtain 14.5 or better. If $> 3$sf, allow answer rounding to 14.5 with no errors in method seen. In multi-step solutions (e.g. using 9.82) interim values may be slightly inaccurate — allow A1 if answer rounds to 14.5 |

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1\\
\includegraphics[max width=\textwidth, alt={}, center]{9e95415c-00f5-4b52-a443-0b946602b3b4-2_426_1244_280_413}

The diagram shows triangle $A B C$, with $A B = 8 \mathrm {~cm}$, angle $B A C = 65 ^ { \circ }$ and angle $B C A = 30 ^ { \circ }$. The point $D$ is on $A C$ such that $A D = 10 \mathrm {~cm}$.\\
(i) Find the area of triangle $A B D$.\\
(ii) Find the length of $B D$.\\
(iii) Find the length of $B C$.

\hfill \mbox{\textit{OCR C2 2014 Q1 [6]}}