OCR C2 2012 June — Question 6 9 marks

Exam BoardOCR
ModuleC2 (Core Mathematics 2)
Year2012
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNumerical integration
TypeShow trapezium rule gives specific value
DifficultyModerate -0.8 This is a straightforward C2 question testing standard trapezium rule application with 2 strips (routine calculation), followed by basic curve sketching to explain overestimate/underestimate, and finally integration of a power function. All parts are textbook exercises requiring only direct application of learned techniques with no problem-solving or novel insight required.
Spec1.08b Integrate x^n: where n != -1 and sums1.08d Evaluate definite integrals: between limits1.09f Trapezium rule: numerical integration

6
  1. Use the trapezium rule, with 2 strips each of width 4 , to show that an approximate value of \(\int _ { 1 } ^ { 9 } 4 \sqrt { x } \mathrm {~d} x\) is \(32 + 16 \sqrt { 5 }\).
  2. Use a sketch graph to explain why the actual value of \(\int _ { 1 } ^ { 9 } 4 \sqrt { x } \mathrm {~d} x\) is greater than \(32 + 16 \sqrt { 5 }\).
  3. Use integration to find the exact value of \(\int _ { 1 } ^ { 9 } 4 \sqrt { x } \mathrm {~d} x\).

Question 6:
Part (i):
AnswerMarks Guidance
AnswerMark Guidance
\(0.5 \times 4 \times (4\sqrt{1} + 8\sqrt{5} + 4\sqrt{9})\)M1* Attempt \(y\)-values at \(x = 1, 5, 9\) only. Must be using \(y\), not integration. Allow slips e.g. \(\sqrt{4x}\) as long as clearly intended as \(y\). Allow decimal equiv for \(y_1\) (8.94). Allow M1 for 4, 20, 72 (omitting \(\sqrt{}\)). M0 if other \(y\)-values found (unless not used in trap rule)
\(= 2(16 + 8\sqrt{5})\)M1d* Attempt correct trapezium rule, inc \(h = 4\). Correct structure including 'big brackets' seen or implied. Allow 2 used for \(\frac{1}{2}h\). Allow slips when calculating \(y\) values, but all other aspects must be correct
\(= 32 + 16\sqrt{5}\) AGA1 Obtain \(32 + 16\sqrt{5}\). Must come from exact working. isw if exact answer found first, then decimal equivalent stated
Part (ii):
AnswerMarks Guidance
AnswerMark Guidance
Sketch showing correct graph of \(y = 4\sqrt{x}\) and two trapeziaB1* Correct graph shown, existing for at least \(1 \leq x \leq 9\). Exactly two trapezia must be shown, of roughly equal widths, with top vertices on the curve
Curve is above tops of trapeziaB1d* Must refer to tops of trapezia. Allow 'trapezium' rather than 'trapezia'. B0 for 'trapezia are below curve' (i.e. 'top' not used). Could shade gaps on diagram but some text also required. B0 for 'some area not calculated' unless clear which area. Concave/convex is B0. B1 for decreasing gradient (but B0 for decreasing curve). No sketch is B0 irrespective of explanation
Part (iii):
AnswerMarks Guidance
AnswerMark Guidance
\(\int_1^9 4x^{\frac{1}{2}}\,dx = \left[\frac{8}{3}x^{\frac{3}{2}}\right]_1^9\)M1 Obtain \(kx^{\frac{3}{2}}\). Any numerical \(k\), including 4. Any exact equiv for the index
\(= 72 - \frac{8}{3}\)A1 Obtain \(\frac{8}{3}x^{\frac{3}{2}}\). Allow unsimplified coefficient, inc \(\frac{4}{1.5}\) or \(\frac{2}{3} \times 4\). Allow non-exact decimal i.e. 2.7, 2.67 etc. Allow \(+ c\)
\(= 69\frac{1}{3}\)M1 Attempt correct use of limits. Must be \(F(9) - F(1)\) i.e. subtraction with limits in correct order. Allow use in any function other than the original, including from differentiation. Allow processing errors e.g. \(\left(\frac{8}{3} \times 9\right)^{1.5}\)
A1Obtain \(69\frac{1}{3}\), or any exact equiv. Allow improper fraction or recurring decimal. A0 for \(69.333\ldots\) A0 for \(69\frac{1}{3} + c\)
## Question 6:

### Part (i):
| Answer | Mark | Guidance |
|--------|------|----------|
| $0.5 \times 4 \times (4\sqrt{1} + 8\sqrt{5} + 4\sqrt{9})$ | M1* | Attempt $y$-values at $x = 1, 5, 9$ only. Must be using $y$, not integration. Allow slips e.g. $\sqrt{4x}$ as long as clearly intended as $y$. Allow decimal equiv for $y_1$ (8.94). Allow M1 for 4, 20, 72 (omitting $\sqrt{}$). M0 if other $y$-values found (unless not used in trap rule) |
| $= 2(16 + 8\sqrt{5})$ | M1d* | Attempt correct trapezium rule, inc $h = 4$. Correct structure including 'big brackets' seen or implied. Allow 2 used for $\frac{1}{2}h$. Allow slips when calculating $y$ values, but all other aspects must be correct |
| $= 32 + 16\sqrt{5}$ **AG** | A1 | Obtain $32 + 16\sqrt{5}$. Must come from exact working. isw if exact answer found first, then decimal equivalent stated |

### Part (ii):
| Answer | Mark | Guidance |
|--------|------|----------|
| Sketch showing correct graph of $y = 4\sqrt{x}$ and two trapezia | B1* | Correct graph shown, existing for at least $1 \leq x \leq 9$. Exactly two trapezia must be shown, of roughly equal widths, with top vertices on the curve |
| Curve is above tops of trapezia | B1d* | Must refer to tops of trapezia. Allow 'trapezium' rather than 'trapezia'. B0 for 'trapezia are below curve' (i.e. 'top' not used). Could shade gaps on diagram but some text also required. B0 for 'some area not calculated' unless clear which area. Concave/convex is B0. B1 for decreasing gradient (but B0 for decreasing curve). No sketch is B0 irrespective of explanation |

### Part (iii):
| Answer | Mark | Guidance |
|--------|------|----------|
| $\int_1^9 4x^{\frac{1}{2}}\,dx = \left[\frac{8}{3}x^{\frac{3}{2}}\right]_1^9$ | M1 | Obtain $kx^{\frac{3}{2}}$. Any numerical $k$, including 4. Any exact equiv for the index |
| $= 72 - \frac{8}{3}$ | A1 | Obtain $\frac{8}{3}x^{\frac{3}{2}}$. Allow unsimplified coefficient, inc $\frac{4}{1.5}$ or $\frac{2}{3} \times 4$. Allow non-exact decimal i.e. 2.7, 2.67 etc. Allow $+ c$ |
| $= 69\frac{1}{3}$ | M1 | Attempt correct use of limits. Must be $F(9) - F(1)$ i.e. subtraction with limits in correct order. Allow use in any function other than the original, including from differentiation. Allow processing errors e.g. $\left(\frac{8}{3} \times 9\right)^{1.5}$ |
| | A1 | Obtain $69\frac{1}{3}$, or any exact equiv. Allow improper fraction or recurring decimal. A0 for $69.333\ldots$ A0 for $69\frac{1}{3} + c$ |

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6 (i) Use the trapezium rule, with 2 strips each of width 4 , to show that an approximate value of $\int _ { 1 } ^ { 9 } 4 \sqrt { x } \mathrm {~d} x$ is $32 + 16 \sqrt { 5 }$.\\
(ii) Use a sketch graph to explain why the actual value of $\int _ { 1 } ^ { 9 } 4 \sqrt { x } \mathrm {~d} x$ is greater than $32 + 16 \sqrt { 5 }$.\\
(iii) Use integration to find the exact value of $\int _ { 1 } ^ { 9 } 4 \sqrt { x } \mathrm {~d} x$.

\hfill \mbox{\textit{OCR C2 2012 Q6 [9]}}