OCR C2 2012 June — Question 3 6 marks

Exam BoardOCR
ModuleC2 (Core Mathematics 2)
Year2012
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRadians, Arc Length and Sector Area
TypeSegment area calculation
DifficultyModerate -0.3 This is a straightforward multi-part question testing standard sector formulas. Part (i) is routine degree-to-radian conversion, part (ii) applies the sector area formula directly to find r, and part (iii) requires subtracting triangle area from sector area—all standard C2 techniques with no novel problem-solving required. Slightly easier than average due to the step-by-step scaffolding.
Spec1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta

3 \includegraphics[max width=\textwidth, alt={}, center]{f25e2580-ba0b-42ce-bf86-63f2c2075223-2_436_526_762_767} The diagram shows a sector \(A O B\) of a circle, centre \(O\) and radius \(r \mathrm {~cm}\). Angle \(A O B\) is \(72 ^ { \circ }\).
  1. Express \(72 ^ { \circ }\) exactly in radians, simplifying your answer. The area of the sector \(A O B\) is \(45 \pi \mathrm {~cm} ^ { 2 }\).
  2. Find the value of \(r\).
  3. Find the area of the segment bounded by the arc \(A B\) and the chord \(A B\), giving your answer correct to 3 significant figures.

Question 3:
Part (i): Convert \(72°\) to radians
AnswerMarks Guidance
AnswerMarks Guidance
\(72° = 72 \times \frac{\pi}{180} = \frac{2\pi}{5}\) radiansB1 State \(\frac{2\pi}{5}\), \(\frac{2}{5}\pi\) or \(0.4\pi\). Must be simplified. B0 for decimal equiv (1.26), but isw if exact simplified value seen but then given in decimals.
[1]
Part (ii): Find radius \(r\)
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{1}{2} \times r^2 \times \frac{2\pi}{5} = 45\pi\), equate attempt at area using \(\frac{1}{2}r^2\theta\) to \(45\pi\) and attempt to solve for \(r\)M1 Condone omission of \(\frac{1}{2}\), but no other error. Must be equated to \(45\pi\). Allow M1 for using 0.4 or \(1.26\pi\). Allow if using incorrect angle from part (i) as long as clearly intended to be in radians.
\(r = 15\) cmA1 Must be exact working only – any use of decimals is A0 (but allow 15.0 if giving previously exact answer to 3sf).
[2]
Part (iii): Find area of segment
AnswerMarks Guidance
AnswerMarks Guidance
Area of triangle \(= \frac{1}{2} \times 15^2 \times \sin\!\left(\frac{2\pi}{5}\right) = 106.99\), attempt area of triangle using \(\frac{1}{2}r^2\sin\theta\)M1* Condone omission of \(\frac{1}{2}\), but no other error. Must be using their \(r\) and angle linked to their \(\theta\). Could be using degrees or radians.
Area of segment \(= 45\pi - 106.99\), attempt \(45\pi -\) area of triangleM1d* Must be using \(45\pi\) (not 45). M0 if area of triangle is greater than \(45\pi\).
\(= 34.4\) cm²A1 If \(>3\)sf then allow any values rounding to 34.4.
[3]
## Question 3:

### Part (i): Convert $72°$ to radians

| Answer | Marks | Guidance |
|--------|-------|----------|
| $72° = 72 \times \frac{\pi}{180} = \frac{2\pi}{5}$ radians | B1 | State $\frac{2\pi}{5}$, $\frac{2}{5}\pi$ or $0.4\pi$. Must be simplified. B0 for decimal equiv (1.26), but isw if exact simplified value seen but then given in decimals. |
| | **[1]** | |

### Part (ii): Find radius $r$

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{1}{2} \times r^2 \times \frac{2\pi}{5} = 45\pi$, equate attempt at area using $\frac{1}{2}r^2\theta$ to $45\pi$ and attempt to solve for $r$ | M1 | Condone omission of $\frac{1}{2}$, but no other error. Must be equated to $45\pi$. Allow M1 for using 0.4 or $1.26\pi$. Allow if using incorrect angle from part (i) as long as clearly intended to be in radians. |
| $r = 15$ cm | A1 | Must be exact working only – any use of decimals is A0 (but allow 15.0 if giving previously exact answer to 3sf). |
| | **[2]** | |

### Part (iii): Find area of segment

| Answer | Marks | Guidance |
|--------|-------|----------|
| Area of triangle $= \frac{1}{2} \times 15^2 \times \sin\!\left(\frac{2\pi}{5}\right) = 106.99$, attempt area of triangle using $\frac{1}{2}r^2\sin\theta$ | M1* | Condone omission of $\frac{1}{2}$, but no other error. Must be using their $r$ and angle linked to their $\theta$. Could be using degrees or radians. |
| Area of segment $= 45\pi - 106.99$, attempt $45\pi -$ area of triangle | M1d* | Must be using $45\pi$ (not 45). M0 if area of triangle is greater than $45\pi$. |
| $= 34.4$ cm² | A1 | If $>3$sf then allow any values rounding to 34.4. |
| | **[3]** | |

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3\\
\includegraphics[max width=\textwidth, alt={}, center]{f25e2580-ba0b-42ce-bf86-63f2c2075223-2_436_526_762_767}

The diagram shows a sector $A O B$ of a circle, centre $O$ and radius $r \mathrm {~cm}$. Angle $A O B$ is $72 ^ { \circ }$.\\
(i) Express $72 ^ { \circ }$ exactly in radians, simplifying your answer.

The area of the sector $A O B$ is $45 \pi \mathrm {~cm} ^ { 2 }$.\\
(ii) Find the value of $r$.\\
(iii) Find the area of the segment bounded by the arc $A B$ and the chord $A B$, giving your answer correct to 3 significant figures.

\hfill \mbox{\textit{OCR C2 2012 Q3 [6]}}