| Exam Board | OCR |
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| Module | FP3 (Further Pure Mathematics 3) |
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| Year | 2015 |
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| Session | June |
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| Topic | Vectors: Cross Product & Distances |
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6 Find the shortest distance between the lines with equations
$$\frac { x - 1 } { 2 } = \frac { y + 2 } { 3 } = \frac { z - 5 } { - 1 } \quad \text { and } \quad \frac { x - 3 } { 4 } = \frac { y - 1 } { - 2 } = \frac { z + 1 } { 3 } .$$