| Exam Board | OCR |
|---|---|
| Module | FP3 (Further Pure Mathematics 3) |
| Year | 2012 |
| Session | June |
| Marks | 11 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Groups |
| Type | Subgroups and cosets |
| Difficulty | Challenging +1.2 This is a Further Maths group theory question requiring subgroup verification using standard axioms and identification of a cyclic subgroup of order 6 (rotations by multiples of 60°). While it involves abstract algebra concepts beyond standard A-level, the actual steps are methodical: checking closure/identity/inverses for part (i), and recognizing geometric rotations for part (ii). The calculations are straightforward once the approach is identified, making it moderately challenging but not requiring deep insight. |
| Spec | 4.03a Matrix language: terminology and notation4.03b Matrix operations: addition, multiplication, scalar4.03c Matrix multiplication: properties (associative, not commutative)8.03f Subgroups: definition and tests for proper subgroups8.03g Cyclic groups: meaning of the term |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| For \(R\), \(\cos^2\theta + \sin^2\theta = 1 \Rightarrow \text{ad} - \text{bc} = 1 \Rightarrow R \subset M\) | B1 | For showing \(R \subset M\) |
| \(R(\theta)R(\phi) = R(\theta + \phi)\) since \(\cos\theta\cos\phi - \sin\theta\sin\phi = \cos(\theta+\phi)\) and \(\pm(\cos\theta\sin\phi + \sin\theta\cos\phi) = \pm\sin(\theta+\phi)\) | M1, A1 | For multiplying 2 distinct elements; for obtaining \(R(\theta)R(\phi) \in R\). Must demonstrate use of compound angles or explain rotations |
| Identity: \(\theta = 0 \Rightarrow \begin{pmatrix}1 & 0\\0 & 1\end{pmatrix} \in R\) | B1 | For identity element related to \(\theta = 0\) |
| Inverse: \(R(-\theta) = \begin{pmatrix}\cos\theta & \sin\theta\\-\sin\theta & \cos\theta\end{pmatrix} = \begin{pmatrix}\cos(-\theta) & -\sin(-\theta)\\\sin(-\theta) & \cos(-\theta)\end{pmatrix}\) | B1, B1 | For inverse element; converted to form of elements of \(R\) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| \(R(\theta)R(\phi)^{-1} = \begin{pmatrix}\cos\theta & -\sin\theta\\\sin\theta & \cos\theta\end{pmatrix}\begin{pmatrix}\cos(-\phi) & -\sin(-\phi)\\\sin(-\phi) & \cos(-\phi)\end{pmatrix}\) | B1, B1, B1, M1, A1 | For \(R \subset M\); considering \(R(\theta)R(\phi)^{-1}\); correct inverse; multiplying elements; correct product |
| \(= \begin{pmatrix}\cos(\theta-\phi) & -\sin(\theta-\phi)\\\sin(\theta-\phi) & \cos(\theta-\phi)\end{pmatrix} \in R\) | ||
| Set is non-empty | B1 | Can be implied by identity element |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| For \(\theta = \frac{1}{3}k\pi\), elements are: \(\begin{pmatrix}1&0\\0&1\end{pmatrix}\), \(\begin{pmatrix}\frac{1}{2} & -\frac{1}{2}\sqrt{3}\\\frac{1}{2}\sqrt{3} & \frac{1}{2}\end{pmatrix}\), \(\begin{pmatrix}-\frac{1}{2} & -\frac{1}{2}\sqrt{3}\\\frac{1}{2}\sqrt{3} & -\frac{1}{2}\end{pmatrix}\), \(\begin{pmatrix}-1&0\\0&-1\end{pmatrix}\), \(\begin{pmatrix}-\frac{1}{2} & \frac{1}{2}\sqrt{3}\\-\frac{1}{2}\sqrt{3} & -\frac{1}{2}\end{pmatrix}\), \(\begin{pmatrix}\frac{1}{2} & \frac{1}{2}\sqrt{3}\\-\frac{1}{2}\sqrt{3} & \frac{1}{2}\end{pmatrix}\) | B1, M1, A1, A1, A1 | For \(\theta = \frac{1}{3}\pi\); for using "their \(\theta\)" in \(\begin{pmatrix}\cos k\theta & \sin k\theta\\-\sin k\theta & \cos k\theta\end{pmatrix}\) for at least 2 values of \(k\); for identity and one other element other than \((-I)\); for 2 more elements; for all 6 elements correct. Allow degrees instead of radians |
## Question 8(i):
**METHOD 1**
| Answer | Mark | Guidance |
|--------|------|----------|
| For $R$, $\cos^2\theta + \sin^2\theta = 1 \Rightarrow \text{ad} - \text{bc} = 1 \Rightarrow R \subset M$ | B1 | For showing $R \subset M$ |
| $R(\theta)R(\phi) = R(\theta + \phi)$ since $\cos\theta\cos\phi - \sin\theta\sin\phi = \cos(\theta+\phi)$ and $\pm(\cos\theta\sin\phi + \sin\theta\cos\phi) = \pm\sin(\theta+\phi)$ | M1, A1 | For multiplying 2 distinct elements; for obtaining $R(\theta)R(\phi) \in R$. Must demonstrate use of compound angles or explain rotations |
| Identity: $\theta = 0 \Rightarrow \begin{pmatrix}1 & 0\\0 & 1\end{pmatrix} \in R$ | B1 | For identity element related to $\theta = 0$ |
| Inverse: $R(-\theta) = \begin{pmatrix}\cos\theta & \sin\theta\\-\sin\theta & \cos\theta\end{pmatrix} = \begin{pmatrix}\cos(-\theta) & -\sin(-\theta)\\\sin(-\theta) & \cos(-\theta)\end{pmatrix}$ | B1, B1 | For inverse element; converted to form of elements of $R$ |
**SR** (subgroup criterion method)
| Answer | Mark | Guidance |
|--------|------|----------|
| $R(\theta)R(\phi)^{-1} = \begin{pmatrix}\cos\theta & -\sin\theta\\\sin\theta & \cos\theta\end{pmatrix}\begin{pmatrix}\cos(-\phi) & -\sin(-\phi)\\\sin(-\phi) & \cos(-\phi)\end{pmatrix}$ | B1, B1, B1, M1, A1 | For $R \subset M$; considering $R(\theta)R(\phi)^{-1}$; correct inverse; multiplying elements; correct product |
| $= \begin{pmatrix}\cos(\theta-\phi) & -\sin(\theta-\phi)\\\sin(\theta-\phi) & \cos(\theta-\phi)\end{pmatrix} \in R$ | | |
| Set is non-empty | B1 | Can be implied by identity element |
---
## Question 8(ii):
| Answer | Mark | Guidance |
|--------|------|----------|
| For $\theta = \frac{1}{3}k\pi$, elements are: $\begin{pmatrix}1&0\\0&1\end{pmatrix}$, $\begin{pmatrix}\frac{1}{2} & -\frac{1}{2}\sqrt{3}\\\frac{1}{2}\sqrt{3} & \frac{1}{2}\end{pmatrix}$, $\begin{pmatrix}-\frac{1}{2} & -\frac{1}{2}\sqrt{3}\\\frac{1}{2}\sqrt{3} & -\frac{1}{2}\end{pmatrix}$, $\begin{pmatrix}-1&0\\0&-1\end{pmatrix}$, $\begin{pmatrix}-\frac{1}{2} & \frac{1}{2}\sqrt{3}\\-\frac{1}{2}\sqrt{3} & -\frac{1}{2}\end{pmatrix}$, $\begin{pmatrix}\frac{1}{2} & \frac{1}{2}\sqrt{3}\\-\frac{1}{2}\sqrt{3} & \frac{1}{2}\end{pmatrix}$ | B1, M1, A1, A1, A1 | For $\theta = \frac{1}{3}\pi$; for using "their $\theta$" in $\begin{pmatrix}\cos k\theta & \sin k\theta\\-\sin k\theta & \cos k\theta\end{pmatrix}$ for at least 2 values of $k$; for identity and one other element other than $(-I)$; for 2 more elements; for all 6 elements correct. Allow degrees instead of radians |
8 The set $M$ of matrices $\left( \begin{array} { l l } a & b \\ c & d \end{array} \right)$, where $a , b , c$ and $d$ are real and $a d - b c = 1$, forms a group $( M , \times )$ under matrix multiplication. $R$ denotes the set of all matrices $\left( \begin{array} { c c } \cos \theta & - \sin \theta \\ \sin \theta & \cos \theta \end{array} \right)$.\\
(i) Prove that ( $R , \times$ ) is a subgroup of ( $M , \times$ ).\\
(ii) By considering geometrical transformations in the $x - y$ plane, find a subgroup of $( R , \times )$ of order 6 . Give the elements of this subgroup in exact numerical form.
\section*{THERE ARE NO QUESTIONS WRITTEN ON THIS PAGE.}
\hfill \mbox{\textit{OCR FP3 2012 Q8 [11]}}