OCR FP3 2012 June — Question 8 11 marks

Exam BoardOCR
ModuleFP3 (Further Pure Mathematics 3)
Year2012
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGroups
TypeSubgroups and cosets
DifficultyChallenging +1.2 This is a Further Maths group theory question requiring subgroup verification using standard axioms and identification of a cyclic subgroup of order 6 (rotations by multiples of 60°). While it involves abstract algebra concepts beyond standard A-level, the actual steps are methodical: checking closure/identity/inverses for part (i), and recognizing geometric rotations for part (ii). The calculations are straightforward once the approach is identified, making it moderately challenging but not requiring deep insight.
Spec4.03a Matrix language: terminology and notation4.03b Matrix operations: addition, multiplication, scalar4.03c Matrix multiplication: properties (associative, not commutative)8.03f Subgroups: definition and tests for proper subgroups8.03g Cyclic groups: meaning of the term

8 The set \(M\) of matrices \(\left( \begin{array} { l l } a & b \\ c & d \end{array} \right)\), where \(a , b , c\) and \(d\) are real and \(a d - b c = 1\), forms a group \(( M , \times )\) under matrix multiplication. \(R\) denotes the set of all matrices \(\left( \begin{array} { c c } \cos \theta & - \sin \theta \\ \sin \theta & \cos \theta \end{array} \right)\).
  1. Prove that ( \(R , \times\) ) is a subgroup of ( \(M , \times\) ).
  2. By considering geometrical transformations in the \(x - y\) plane, find a subgroup of \(( R , \times )\) of order 6 . Give the elements of this subgroup in exact numerical form. \section*{THERE ARE NO QUESTIONS WRITTEN ON THIS PAGE.}

Question 8(i):
METHOD 1
AnswerMarks Guidance
AnswerMark Guidance
For \(R\), \(\cos^2\theta + \sin^2\theta = 1 \Rightarrow \text{ad} - \text{bc} = 1 \Rightarrow R \subset M\)B1 For showing \(R \subset M\)
\(R(\theta)R(\phi) = R(\theta + \phi)\) since \(\cos\theta\cos\phi - \sin\theta\sin\phi = \cos(\theta+\phi)\) and \(\pm(\cos\theta\sin\phi + \sin\theta\cos\phi) = \pm\sin(\theta+\phi)\)M1, A1 For multiplying 2 distinct elements; for obtaining \(R(\theta)R(\phi) \in R\). Must demonstrate use of compound angles or explain rotations
Identity: \(\theta = 0 \Rightarrow \begin{pmatrix}1 & 0\\0 & 1\end{pmatrix} \in R\)B1 For identity element related to \(\theta = 0\)
Inverse: \(R(-\theta) = \begin{pmatrix}\cos\theta & \sin\theta\\-\sin\theta & \cos\theta\end{pmatrix} = \begin{pmatrix}\cos(-\theta) & -\sin(-\theta)\\\sin(-\theta) & \cos(-\theta)\end{pmatrix}\)B1, B1 For inverse element; converted to form of elements of \(R\)
SR (subgroup criterion method)
AnswerMarks Guidance
AnswerMark Guidance
\(R(\theta)R(\phi)^{-1} = \begin{pmatrix}\cos\theta & -\sin\theta\\\sin\theta & \cos\theta\end{pmatrix}\begin{pmatrix}\cos(-\phi) & -\sin(-\phi)\\\sin(-\phi) & \cos(-\phi)\end{pmatrix}\)B1, B1, B1, M1, A1 For \(R \subset M\); considering \(R(\theta)R(\phi)^{-1}\); correct inverse; multiplying elements; correct product
\(= \begin{pmatrix}\cos(\theta-\phi) & -\sin(\theta-\phi)\\\sin(\theta-\phi) & \cos(\theta-\phi)\end{pmatrix} \in R\)
Set is non-emptyB1 Can be implied by identity element
Question 8(ii):
AnswerMarks Guidance
AnswerMark Guidance
For \(\theta = \frac{1}{3}k\pi\), elements are: \(\begin{pmatrix}1&0\\0&1\end{pmatrix}\), \(\begin{pmatrix}\frac{1}{2} & -\frac{1}{2}\sqrt{3}\\\frac{1}{2}\sqrt{3} & \frac{1}{2}\end{pmatrix}\), \(\begin{pmatrix}-\frac{1}{2} & -\frac{1}{2}\sqrt{3}\\\frac{1}{2}\sqrt{3} & -\frac{1}{2}\end{pmatrix}\), \(\begin{pmatrix}-1&0\\0&-1\end{pmatrix}\), \(\begin{pmatrix}-\frac{1}{2} & \frac{1}{2}\sqrt{3}\\-\frac{1}{2}\sqrt{3} & -\frac{1}{2}\end{pmatrix}\), \(\begin{pmatrix}\frac{1}{2} & \frac{1}{2}\sqrt{3}\\-\frac{1}{2}\sqrt{3} & \frac{1}{2}\end{pmatrix}\)B1, M1, A1, A1, A1 For \(\theta = \frac{1}{3}\pi\); for using "their \(\theta\)" in \(\begin{pmatrix}\cos k\theta & \sin k\theta\\-\sin k\theta & \cos k\theta\end{pmatrix}\) for at least 2 values of \(k\); for identity and one other element other than \((-I)\); for 2 more elements; for all 6 elements correct. Allow degrees instead of radians
## Question 8(i):

**METHOD 1**

| Answer | Mark | Guidance |
|--------|------|----------|
| For $R$, $\cos^2\theta + \sin^2\theta = 1 \Rightarrow \text{ad} - \text{bc} = 1 \Rightarrow R \subset M$ | B1 | For showing $R \subset M$ |
| $R(\theta)R(\phi) = R(\theta + \phi)$ since $\cos\theta\cos\phi - \sin\theta\sin\phi = \cos(\theta+\phi)$ and $\pm(\cos\theta\sin\phi + \sin\theta\cos\phi) = \pm\sin(\theta+\phi)$ | M1, A1 | For multiplying 2 distinct elements; for obtaining $R(\theta)R(\phi) \in R$. Must demonstrate use of compound angles or explain rotations |
| Identity: $\theta = 0 \Rightarrow \begin{pmatrix}1 & 0\\0 & 1\end{pmatrix} \in R$ | B1 | For identity element related to $\theta = 0$ |
| Inverse: $R(-\theta) = \begin{pmatrix}\cos\theta & \sin\theta\\-\sin\theta & \cos\theta\end{pmatrix} = \begin{pmatrix}\cos(-\theta) & -\sin(-\theta)\\\sin(-\theta) & \cos(-\theta)\end{pmatrix}$ | B1, B1 | For inverse element; converted to form of elements of $R$ |

**SR** (subgroup criterion method)

| Answer | Mark | Guidance |
|--------|------|----------|
| $R(\theta)R(\phi)^{-1} = \begin{pmatrix}\cos\theta & -\sin\theta\\\sin\theta & \cos\theta\end{pmatrix}\begin{pmatrix}\cos(-\phi) & -\sin(-\phi)\\\sin(-\phi) & \cos(-\phi)\end{pmatrix}$ | B1, B1, B1, M1, A1 | For $R \subset M$; considering $R(\theta)R(\phi)^{-1}$; correct inverse; multiplying elements; correct product |
| $= \begin{pmatrix}\cos(\theta-\phi) & -\sin(\theta-\phi)\\\sin(\theta-\phi) & \cos(\theta-\phi)\end{pmatrix} \in R$ | | |
| Set is non-empty | B1 | Can be implied by identity element |

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## Question 8(ii):

| Answer | Mark | Guidance |
|--------|------|----------|
| For $\theta = \frac{1}{3}k\pi$, elements are: $\begin{pmatrix}1&0\\0&1\end{pmatrix}$, $\begin{pmatrix}\frac{1}{2} & -\frac{1}{2}\sqrt{3}\\\frac{1}{2}\sqrt{3} & \frac{1}{2}\end{pmatrix}$, $\begin{pmatrix}-\frac{1}{2} & -\frac{1}{2}\sqrt{3}\\\frac{1}{2}\sqrt{3} & -\frac{1}{2}\end{pmatrix}$, $\begin{pmatrix}-1&0\\0&-1\end{pmatrix}$, $\begin{pmatrix}-\frac{1}{2} & \frac{1}{2}\sqrt{3}\\-\frac{1}{2}\sqrt{3} & -\frac{1}{2}\end{pmatrix}$, $\begin{pmatrix}\frac{1}{2} & \frac{1}{2}\sqrt{3}\\-\frac{1}{2}\sqrt{3} & \frac{1}{2}\end{pmatrix}$ | B1, M1, A1, A1, A1 | For $\theta = \frac{1}{3}\pi$; for using "their $\theta$" in $\begin{pmatrix}\cos k\theta & \sin k\theta\\-\sin k\theta & \cos k\theta\end{pmatrix}$ for at least 2 values of $k$; for identity and one other element other than $(-I)$; for 2 more elements; for all 6 elements correct. Allow degrees instead of radians |
8 The set $M$ of matrices $\left( \begin{array} { l l } a & b \\ c & d \end{array} \right)$, where $a , b , c$ and $d$ are real and $a d - b c = 1$, forms a group $( M , \times )$ under matrix multiplication. $R$ denotes the set of all matrices $\left( \begin{array} { c c } \cos \theta & - \sin \theta \\ \sin \theta & \cos \theta \end{array} \right)$.\\
(i) Prove that ( $R , \times$ ) is a subgroup of ( $M , \times$ ).\\
(ii) By considering geometrical transformations in the $x - y$ plane, find a subgroup of $( R , \times )$ of order 6 . Give the elements of this subgroup in exact numerical form.

\section*{THERE ARE NO QUESTIONS WRITTEN ON THIS PAGE.}

\hfill \mbox{\textit{OCR FP3 2012 Q8 [11]}}