OCR FP3 2009 January — Question 6 13 marks

Exam BoardOCR
ModuleFP3 (Further Pure Mathematics 3)
Year2009
SessionJanuary
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors: Lines & Planes
TypeAngle between two planes
DifficultyStandard +0.8 This is a multi-part 3D vectors question requiring finding a plane equation from three points, calculating angle between planes using normal vectors, and finding intersection of line with plane. While systematic, it demands solid spatial reasoning, coordinate work with a cuboid, and multiple vector techniques across three connected parts—above average for A-level but standard for FP3.
Spec4.04b Plane equations: cartesian and vector forms4.04d Angles: between planes and between line and plane4.04f Line-plane intersection: find point

6
The cuboid \(O A B C D E F G\) shown in the diagram has \(\overrightarrow { O A } = 4 \mathbf { i } , \overrightarrow { O C } = 2 \mathbf { j } , \overrightarrow { O D } = 3 \mathbf { k }\), and \(M\) is the mid-point of \(G F\).
  1. Find the equation of the plane \(A C G E\), giving your answer in the form \(\mathbf{r} \cdot \mathbf{n} = p\).
  2. The plane \(O E F C\) has equation \(\mathbf { r } \cdot ( 3 \mathbf { i } - 4 \mathbf { k } ) = 0\). Find the acute angle between the planes \(O E F C\) and \(A C G E\).
  3. The line \(A M\) meets the plane \(O E F C\) at the point \(W\). Find the ratio \(A W : W M\).

Question 6:
Part (i) Method 1:
AnswerMarks Guidance
Answer/WorkingMark Guidance
Use 2 of \([-4,2,0],[0,0,3],[-4,2,3],[4,-2,3]\) or multiplesM1 For finding vector product of 2 appropriate vectors in plane \(ACGE\)
\(\mathbf{n} = k[1,2,0]\)A1 For correct n
Use \(A[4,0,0]\), \(C[0,2,0]\), \(G[0,2,3]\) or \(E[4,0,3]\)M1 For substituting a point in the plane
\(\mathbf{r}.[1,2,0] = 4\)A1 4 For correct equation. AEF in this form
Part (i) Method 2:
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\mathbf{r} = [4,0,0] + \lambda[-4,2,0] + \mu[0,0,3]\)M1 For writing plane in 2-parameter form
\(\Rightarrow x = 4 - 4\lambda\), \(y = 2\lambda\), \(z = 3\mu\)A1 For 3 correct equations
\(x + 2y = 4\)M1 For eliminating \(\lambda\) (and \(\mu\))
\(\Rightarrow \mathbf{r}.[1,2,0] = 4\)A1 For correct equation. AEF in this form
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\theta = \cos^{-1}\frac{[3,0,-4]\cdot[1,2,0] }{\sqrt{3^2+0^2+4^2}\sqrt{1^2+2^2+0^2}}\)
\(\theta = \cos^{-1}\frac{3}{5\sqrt{5}} = 74.4°\)A1 4 For correct angle
Part (iii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(AM\): \((\mathbf{r} =)[4,0,0] + t[-2,2,3]\) (or \([2,2,3] + t[-2,2,3]\))M1, A1 For obtaining parametric expression for \(AM\); For correct expression seen or implied
\(3(4-2t) - 4(3t) = 0\) (or \(3(2-2t) - 4(3+3t) = 0\))M1 For finding intersection of \(AM\) with \(ACGE\)
\(t = \frac{2}{3}\) (or \(t = -\frac{1}{3}\)) OR \(\mathbf{w} = \left[\frac{8}{3}, \frac{4}{3}, 2\right]\)A1 For correct \(t\) OR position vector
\(AW : WM = 2:1\)A1 5 For correct ratio
Total: 13 marks
# Question 6:

## Part (i) Method 1:

| Answer/Working | Mark | Guidance |
|---|---|---|
| Use 2 of $[-4,2,0],[0,0,3],[-4,2,3],[4,-2,3]$ or multiples | M1 | For finding vector product of 2 appropriate vectors in plane $ACGE$ |
| $\mathbf{n} = k[1,2,0]$ | A1 | For correct **n** |
| Use $A[4,0,0]$, $C[0,2,0]$, $G[0,2,3]$ or $E[4,0,3]$ | M1 | For substituting a point in the plane |
| $\mathbf{r}.[1,2,0] = 4$ | A1 **4** | For correct equation. **AEF** in this form |

## Part (i) Method 2:

| Answer/Working | Mark | Guidance |
|---|---|---|
| $\mathbf{r} = [4,0,0] + \lambda[-4,2,0] + \mu[0,0,3]$ | M1 | For writing plane in 2-parameter form |
| $\Rightarrow x = 4 - 4\lambda$, $y = 2\lambda$, $z = 3\mu$ | A1 | For 3 correct equations |
| $x + 2y = 4$ | M1 | For eliminating $\lambda$ (and $\mu$) |
| $\Rightarrow \mathbf{r}.[1,2,0] = 4$ | A1 | For correct equation. **AEF** in this form |

## Part (ii):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $\theta = \cos^{-1}\frac{|[3,0,-4]\cdot[1,2,0]|}{\sqrt{3^2+0^2+4^2}\sqrt{1^2+2^2+0^2}}$ | B1$\sqrt{}$, M1, M1 | For using correct vectors (allow multiples), f.t. from **n**; For using scalar product; For multiplying both moduli in denominator |
| $\theta = \cos^{-1}\frac{3}{5\sqrt{5}} = 74.4°$ | A1 **4** | For correct angle |

## Part (iii):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $AM$: $(\mathbf{r} =)[4,0,0] + t[-2,2,3]$ (or $[2,2,3] + t[-2,2,3]$) | M1, A1 | For obtaining parametric expression for $AM$; For correct expression seen or implied |
| $3(4-2t) - 4(3t) = 0$ (or $3(2-2t) - 4(3+3t) = 0$) | M1 | For finding intersection of $AM$ with $ACGE$ |
| $t = \frac{2}{3}$ (or $t = -\frac{1}{3}$) OR $\mathbf{w} = \left[\frac{8}{3}, \frac{4}{3}, 2\right]$ | A1 | For correct $t$ OR position vector |
| $AW : WM = 2:1$ | A1 **5** | For correct ratio |

**Total: 13 marks**

---
6\\
\begin{tikzpicture}[thick, >=Stealth]

  % Projection parameters: depth direction in 2D
  \pgfmathsetmacro{\ax}{0.7}   % x-component per unit depth
  \pgfmathsetmacro{\ay}{0.5}   % y-component per unit depth

  % --- Vertices ---
  % Bottom face
  \coordinate (O) at (0, 0);
  \coordinate (A) at (4, 0);
  \coordinate (B) at ({4 + 2*\ax}, {2*\ay});
  \coordinate (C) at ({2*\ax}, {2*\ay});
  % Top face
  \coordinate (D) at (0, 3);
  \coordinate (E) at (4, 3);
  \coordinate (F) at ({4 + 2*\ax}, {3 + 2*\ay});
  \coordinate (G) at ({2*\ax}, {3 + 2*\ay});
  % Midpoint of edge GF
  \coordinate (M) at ({0.5*(4 + 4*\ax)}, {3 + 2*\ay});

  % --- Hidden edges (dashed) ---
  \draw[dashed] (O) -- (C) -- (B);
  \draw[dashed] (C) -- (G);

  % --- Visible edges (solid) ---
  % Bottom
  \draw (O) -- (A) -- (B);
  % Top
  \draw (D) -- (G) -- (F) -- (E) -- (D);
  % Verticals
  \draw (O) -- (D);
  \draw (A) -- (E);
  \draw (B) -- (F);

  % --- Vertex labels ---
  \node[below left]  at (O) {$O$};
  \node[below]        at (A) {$A$};
  \node[right]        at (B) {$B$};
  \node[above left, xshift=2pt]  at (C) {$C$};
  \node[left]         at (D) {$D$};
  \node[below right]  at (E) {$E$};
  \node[above right]  at (F) {$F$};
  \node[above]        at (G) {$G$};
  \node[above]        at (M) {$M$};

  % --- Dots at key points ---
  \fill (M) circle (1.5pt);

  % --- Dimension arrows ---
  \draw[->] (O) -- node[pos=1,below] {$4\mathbf{i}$} ($(O)!0.7!(A)$);
  \draw[->] (O) -- node[left, pos=1] {$3\mathbf{k}$} ($(O)!0.6!(D)$);
  \draw[->] (O) -- node[above] {$2\mathbf{j}$} (C);

\end{tikzpicture}

The cuboid $O A B C D E F G$ shown in the diagram has $\overrightarrow { O A } = 4 \mathbf { i } , \overrightarrow { O C } = 2 \mathbf { j } , \overrightarrow { O D } = 3 \mathbf { k }$, and $M$ is the mid-point of $G F$.\\
(i) Find the equation of the plane $A C G E$, giving your answer in the form $\mathbf{r} \cdot \mathbf{n} = p$.\\
(ii) The plane $O E F C$ has equation $\mathbf { r } \cdot ( 3 \mathbf { i } - 4 \mathbf { k } ) = 0$. Find the acute angle between the planes $O E F C$ and $A C G E$.\\
(iii) The line $A M$ meets the plane $O E F C$ at the point $W$. Find the ratio $A W : W M$.

\hfill \mbox{\textit{OCR FP3 2009 Q6 [13]}}