Edexcel AEA 2005 June — Question 5 19 marks

Exam BoardEdexcel
ModuleAEA (Advanced Extension Award)
Year2005
SessionJune
Marks19
PaperDownload PDF ↗
TopicVectors: Lines & Planes
TypeLine intersection with line
DifficultyChallenging +1.2 This is a structured multi-part vectors question with standard techniques throughout. Parts (a)-(c) involve routine direction vector calculation and line intersection. Parts (d)-(g) require angle calculation, perpendicular distance formula, and angle bisector—all standard A-level Further Maths content. While lengthy (7 parts), each step follows predictably from the previous one with no novel insights required. The AEA context suggests slightly above-average difficulty, but the scaffolding and straightforward methods keep it accessible.
Spec1.10b Vectors in 3D: i,j,k notation1.10c Magnitude and direction: of vectors1.10f Distance between points: using position vectors

5.The point \(A\) has position vector \(7 \mathbf { i } + 2 \mathbf { j } - 7 \mathbf { k }\) and the point \(B\) has position vector \(12 \mathbf { i } + 3 \mathbf { j } - 15 \mathbf { k }\) .
  1. Find a vector for the line \(L _ { 1 }\) which passes through \(A\) and \(B\) . The line \(L _ { 2 }\) has vector equation $$\mathbf { r } = - 4 \mathbf { i } + 12 \mathbf { k } + \mu ( \mathbf { i } - 3 \mathbf { k } )$$
  2. Show that \(L _ { 2 }\) passes through the origin \(O\) .
  3. Show that \(L _ { 1 }\) and \(L _ { 2 }\) intersect at a point \(C\) and find the position vector of \(C\) .
  4. Find the cosine of \(\angle O C A\) .
  5. Hence,or otherwise,find the shortest distance from \(O\) to \(L _ { 1 }\) .
  6. Show that \(| \overrightarrow { C O } | = | \overrightarrow { A B } |\) .
  7. Find a vector equation for the line which bisects \(\angle O C A\) . \includegraphics[max width=\textwidth, alt={}, center]{f9d3e02c-cef2-435b-9cda-76c43fcac575-4_922_1054_279_586} Figure 1 shows a sketch of part of the curve with equation \(y = \mathrm { f } ( x )\), where $$\mathrm { f } ( x ) = x \left( 12 - x ^ { 2 } \right) .$$ The curve cuts the \(x\)-axis at the points \(P , O\) and \(R\), and \(Q\) is the maximum point.

5.The point $A$ has position vector $7 \mathbf { i } + 2 \mathbf { j } - 7 \mathbf { k }$ and the point $B$ has position vector $12 \mathbf { i } + 3 \mathbf { j } - 15 \mathbf { k }$ .
\begin{enumerate}[label=(\alph*)]
\item Find a vector for the line $L _ { 1 }$ which passes through $A$ and $B$ .

The line $L _ { 2 }$ has vector equation

$$\mathbf { r } = - 4 \mathbf { i } + 12 \mathbf { k } + \mu ( \mathbf { i } - 3 \mathbf { k } )$$
\item Show that $L _ { 2 }$ passes through the origin $O$ .
\item Show that $L _ { 1 }$ and $L _ { 2 }$ intersect at a point $C$ and find the position vector of $C$ .
\item Find the cosine of $\angle O C A$ .
\item Hence,or otherwise,find the shortest distance from $O$ to $L _ { 1 }$ .
\item Show that $| \overrightarrow { C O } | = | \overrightarrow { A B } |$ .
\item Find a vector equation for the line which bisects $\angle O C A$ .\\
\includegraphics[max width=\textwidth, alt={}, center]{f9d3e02c-cef2-435b-9cda-76c43fcac575-4_922_1054_279_586}

Figure 1 shows a sketch of part of the curve with equation $y = \mathrm { f } ( x )$, where

$$\mathrm { f } ( x ) = x \left( 12 - x ^ { 2 } \right) .$$

The curve cuts the $x$-axis at the points $P , O$ and $R$, and $Q$ is the maximum point.
\end{enumerate}

\hfill \mbox{\textit{Edexcel AEA 2005 Q5 [19]}}